Draw the image of <EFG after the transformation. identify the type of transformation
1 answer:
The transformation (x,y) --> (x,-y) is reflection over x axis. while the x coordinates in the image stay the same as the original, y coordinates change the sign.
Therefore coordinates of original image and final image after reflection
E - (0,3) --> E' (0,-3)
F - (2,2) --> F' (2,-2)
G - (1,1) --> G' (1,-1)
The diagram attached shows both the original image and image after reflection
Therefore coordinates of original image and final image after reflection
E - (0,3) --> E' (0,-3)
F - (2,2) --> F' (2,-2)
G - (1,1) --> G' (1,-1)
The diagram attached shows both the original image and image after reflection
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Answer:
ln (m^2n^9)
Step-by-step explanation:
Rule: ln a + ln b = ln ab
Rule: ln a^n = n * ln a
2 ln m + 9 ln n =
= ln m^2 + ln n^9
= ln (m^2n^9)
=