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o-na [289]
3 years ago
12

Draw the image of <EFG after the transformation. identify the type of transformation

Mathematics
1 answer:
pav-90 [236]3 years ago
7 0
The transformation (x,y) --> (x,-y) is reflection over x axis. while the x coordinates in the image stay the same as the original, y coordinates change the sign. 
Therefore coordinates of original image and final image after reflection 
E - (0,3) --> E' (0,-3)
F - (2,2) --> F' (2,-2)
G - (1,1) --> G' (1,-1)
The diagram attached shows both the original image and image after reflection

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poizon [28]

Answer:

x=-\frac{11}{18}

Step-by-step explanation:

-1\frac{7}{9}=(-2\frac{5}{6} + \frac{1}{3})x

Solve parenthesis first

-2\frac{5}{6}  + 1/3

Find a common denominator.

The common denominator would be 6.

Because the first expression already has a denominator of 6 it stays the same.

\frac{1}{3} = \frac{2}{6}

-2\frac{5}{6} + \frac{2}{6} = -2\frac{7}{6} = -1\frac{1}{6}

Put that into the original equation.

-1\frac{7}{9}=(-1\frac{1}{6} )x

Isolate the x. Add 1\frac{1}{6} to each side.

-1\frac{7}{9}+ 1\frac{1}{6}=x

Find a common denominator.

we can use 18 as the common denominator.

-1\frac{7}{9}+ 1\frac{1}{6}= -1 \frac{14}{18} +1\frac{3}{18}= x

Add.

-\frac{11}{18} =x

We cannot simplify so our answer stays the same.

6 0
2 years ago
Identify the property used in the first five steps to solve the equation 2(x-5)-6x=-22
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Hope this helps!!!
8 0
3 years ago
Read 2 more answers
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