Draw the image of <EFG after the transformation. identify the type of transformation
1 answer:
The transformation (x,y) --> (x,-y) is reflection over x axis. while the x coordinates in the image stay the same as the original, y coordinates change the sign.
Therefore coordinates of original image and final image after reflection
E - (0,3) --> E' (0,-3)
F - (2,2) --> F' (2,-2)
G - (1,1) --> G' (1,-1)
The diagram attached shows both the original image and image after reflection
Therefore coordinates of original image and final image after reflection
E - (0,3) --> E' (0,-3)
F - (2,2) --> F' (2,-2)
G - (1,1) --> G' (1,-1)
The diagram attached shows both the original image and image after reflection
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Answer:
Step-by-step explanation:
First, on the right-hand side of the equation, let's distribute the to each term in the parenthesis:
Now, let's move all the terms with an to the left-hand side, and everything else to the right-hand side of the equation:
Let's combine like terms:
Finally, let's divide each side by to get
by itself on the left-hand side of the equation: