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4 years ago

Write two different pairs of negative integers x and y, that make the statement x-y=2 true.

Mathematics

2 answers:

Contact [7]4 years ago

8 0

Answer:

x = -1

y = -3 or

x = -3

y = -5

Step-by-step explanation:

-1 - (-3) =

-1 + 3 = 2

-3 - (-5) =

-3 + 5 = 2

arlik [135]4 years ago

3 0

Answer:

It can be any negative pair of numbers that when you substitute in the equation you get 2 as an answer,

For example:

x = -17 and y = -19

x= - 5 and y = -7

x= -3 and y = -5

Step-by-step explanation:

Negative integers are all the negative numbers or all the numbers below 0.

So, in this case, you have to look for negative numbers that if you put in the equation you get 2.

x-y=2

In this equation it says that you need to subtract y from x, (-y), if y has to be a negative number, if, for example, we say that y = -4 then we will have this after substituting in the equation:

x - (-4) = 2

If we have two negative together multiplying like in this case - (-4) then it becomes positive:

-(-4) = +4, because equal sings make a positive.

If we substitute in the original equation we have:

x + 4 = 2

Now we can get the answer for x

x = 2-4

x= - 2

If we send y to the other side of the equation,

x= 2+y, every time we choose a negative number for y we will have a number for x that is y plus 2. This is why you can get any negative number for one variable and then substitute in this equation x= 2+y and get a result for the other variable.

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Does anybody have the answer

Gwar [14]

Answer:

You're answer is right it is -2,2

Step-by-step explanation:

remember x comes before y

7 0

3 years ago

Which choices are equivalent to the expression below? Check all that apply. 5 square root 3

blsea [12.9K]

Option A: $\sqrt{75}$

Option C: $\sqrt{15} \cdot \sqrt{5}$

Option F: $\sqrt{25} \cdot \sqrt{3}$

Solution:

Given expression is $5 \sqrt{3}$ .

Option A: $\sqrt{75}$

$\sqrt{75}=\sqrt{25\times3}$

$=\sqrt{5^2\times3}$

$=5\sqrt{3}$

Hence $\sqrt{75}$ is equivalent expression of $5 \sqrt{3}$ .

Option B: $\sqrt{45}$

$\sqrt{45}=\sqrt{9\times5}$

$=\sqrt{3^2\times5}$

$=3\sqrt{5}$

Hence $\sqrt{45}$ is not equivalent expression of $5 \sqrt{3}$ .

Option C: $\sqrt{15} \cdot \sqrt{5}$

$\sqrt{15} \cdot \sqrt{5}=\sqrt{15\times5}$

$=\sqrt{75}$

$=5\sqrt{3}$ (proved in option A)

Hence $\sqrt{15} \cdot \sqrt{5}$ is equivalent expression of $5 \sqrt{3}$ .

Option D: $\sqrt{3} \cdot \sqrt{5}$

$\sqrt{3} \cdot \sqrt{5}=\sqrt{3\times5}$

$=\sqrt{15}$

Hence $\sqrt{3} \cdot \sqrt{5}$ is not equivalent expression of $5 \sqrt{3}$ .

Option E: 75

75 is a whole number.

Hence 75 is not equivalent expression of $5 \sqrt{3}$ .

Option F: $\sqrt{25} \cdot \sqrt{3}$

$\sqrt{25} \cdot \sqrt{3}=\sqrt{25\times3}$

$=\sqrt{75}$

$=5\sqrt{3}$ (proved in option A)

Hence $\sqrt{25} \cdot \sqrt{3}$ is equivalent expression of $5 \sqrt{3}$ .

Therefore, $\sqrt{75},\ \ \sqrt{15} \cdot \sqrt{5}, \ \ \sqrt{25} \cdot \sqrt{3}$ are all equivalent expressions of $5 \sqrt{3}$ .

6 0

3 years ago

At Gallicum Enterprises, all employees are in one of three categories: J, K, or L. The ratio of the numbers of employees in J to

MrRa [10]

Answer:

380.

Step-by-step explanation:

Given:

Total number of employees at Gallicum Enterprises are in the ratio,

J : k : L = 1 : 3 : 5 for some time.

Last month, 20 new J employees were hired, and no employees left and the new ratio of J to K is now 1 : 2.

Question asked:

What is the new total number of employees at Gallicum Enterprises ?

Solution:

As given, J : K : L = 1 : 3 : 5 

So, J : K = 1 : 3

$\frac{J}{K} = \frac{1}{3} \ (1)$

As last month, 20 new J employees were hired, new ratio of J to K is now

1 : 2.

So, $\frac{J+20}{K}=\frac{1}{2} \ (2)$

Dividing equation 1 and 2,

$\frac{J}{K}\div{\frac{J+20}{K} } = \frac{1}{3}\div{\frac{1}{2} }$

$\frac{J}{K}\times{\frac{K}{J+20} } = \frac{1}{3}\times{\frac{2}{1} }\\\\ \frac{J}{J+20} =\frac{2}{3} \\\\$

By cross multiplication:

$3J=2(J+20)\\3J=2J+40$

Subtracting both sides by $2J$

$J=40$

From equation 1.

$\frac{J}{K} = \frac{1}{3} \\\\ \frac{40}{K} =\frac{1}{3} \\\\$

By cross multiplication:

$K=40\times3\\\\ K=120$

As given, J : K : L = 1 : 3 : 5

So, K : L = 3 : 5

$\frac{K}{L} =\frac{3}{5} \\\\\\ \frac{120}{L} =\frac{3}{5}$

By cross multiplication:

$120\times5=3\times L\\600=3L$

Dividing both sides by 3

$L =200$

New total number of employees after hiring 20 new J employees :

New J + K + L = (New J = J + 20 = 40 + 20 = 60 )

60 + 120 + 200 = 380

Therefore, the new total number of employees at Gallicum Enterprises is 380.

4 0

3 years ago

Sally gets a cup of coffee and a muffin every day for breakfast from one of the many coffee shops in her neighborhood. She picks

aniked [119]

Answer:

A. Mean of the amount Sally spends on breakfast daily = $ 3.90

Standard deviation of the amount Sally spends on breakfast daily = $ 0.34 (rounding to the next cent)

B. Mean of the amount Sally spends on breakfast weekly = $ 27.30

Standard deviation of the amount Sally spends on breakfast weekly = $ 0.89 (rounding to the next cent)

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Average price of a cup of coffee = $ 1.40

Standard deviation = $0.30

Average price of a muffin = $ 2.50

Standard deviation = $ 0.15

The two prices are independent of each other

2. What is the mean and standard deviation of the amount Sally spends on breakfast daily?

Let's recall that:

1. The mean of the sum of two independent variables is the sum of their means.

2. The variance of the sum of two independent variables is equal to the sum of their variances.

Therefore,

Mean of the amount Sally spends on breakfast daily = Average price of a cup of coffee + Average price of a muffin

Replacing with the values we know:

Mean of the amount Sally spends on breakfast daily = 1.40 + 2.50

Mean of the amount Sally spends on breakfast daily = $ 3.90

Variance of the amount Sally spends on breakfast daily = Variance of the price of a cup of coffee + Variance of the price of a muffin

Replacing with the values we know:

Variance of the amount Sally spends on breakfast daily = 0.30² + 0.15²

Variance of the amount Sally spends on breakfast daily = 0.1125

Standard deviation of the amount Sally spends on breakfast daily = √0.1125

Standard deviation of the amount Sally spends on breakfast daily = $ 0.34 (rounding to the next cent)

3. What is the mean and standard deviation of the amount she spends on breakfast weekly (7 days)?

Mean of the amount Sally spends on breakfast weekly = 7 * Mean of the amount Sally spends on breakfast daily

Mean of the amount Sally spends on breakfast weekly = 7 * 3.90

Mean of the amount Sally spends on breakfast weekly = $ 27.30

Variance of the amount Sally spends on breakfast weekly = 7 * Variance of the amount Sally spends on breakfast daily

Variance of the amount Sally spends on breakfast weekly = 7 * 0.1125

Variance of the amount Sally spends on breakfast weekly = 0.7875

Standard deviation of the amount Sally spends on breakfast weekly = √0.7875

Standard deviation of the amount Sally spends on breakfast weekly = $ 0.89 (rounding to the next cent)

3 0

4 years ago

How to do this?? give me a solution its confusing me?!!

Alika [10]

Answer:

t = 3h

Step-by-step explanation:

Given

h = $\frac{1}{3}$ t

Multiply both sides by 3 to clear the fraction

3h = t

5 0

4 years ago