Find the median and mean of the
2 answers:
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Answer with explanation:
Number of four digit numbers using four distinct digit
=Unit placed can be filled in four ways * Tens place can be filled in Three ways * Hundreds place can be filled in 2 ways * Thousand Place can be filled in a single way
=4*3*2*1
=24 distinct numbers
Sum of all four , four digits numbers using 1,2,3,4
= (If we keep 4 at unit place +Keeping 3 at unit place +Keeping 2 at unit place+Keeping 1 at unit place)×6+At tens place (2*2+3*2+1*2+4*2+2*2+1*2+1*2+3*2+4*2+2*2+3*2+4*2)+At hundred's place (2*2+3*2+1*2+4*2+2*2+1*2+1*2+3*2+4*2+2*2+3*2+4*2)+At thousand's Place(2*2+3*2+1*2+4*2+2*2+1*2+1*2+3*2+4*2+2*2+3*2+4*2)
=(24+18+12+6)Unit place+(60)Ten's place +(60)Hundred's place+(60)Thousand's Place
=66660
Answer:
The dimensions are x =20 and y=20 of the garden that will maximize its area is 400
Step-by-step explanation:
Step 1:-
let 'x' be the length and the 'y' be the width of the rectangle
given Jenna's buys 80ft of fencing of rectangle so the perimeter of the rectangle is 2(x +y) = 80
x + y =40
y = 40 -x
now the area of the rectangle A = length X width
A = x y
substitute 'y' value in above A = x (40 - x)
A = 40 x - x^2 .....(1)
<u>Step :2</u>
now differentiating equation (1) with respective to 'x'
........(2)
<u>Find the dimensions</u>
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40 - 2x =0
40 = 2x
x = 20
and y = 40 - x = 40 -20 =20
The dimensions are x =20 and y=20
length = 20 and breadth = 20
<u>Step 3</u>:-
we have to find maximum area
Again differentiating equation (2) with respective to 'x' we get
Now the maximum area A = x y at x =20 and y=20
A = 20 X 20 = 400
<u>Conclusion</u>:-
The dimensions are x =20 and y=20 of the garden that will maximize its area is 400
<u>verification</u>:-
The perimeter = 2(x +y) =80
2(20 +20) =80
2(40) =80
80 =80