<em><u>The equation of the line passing through the point (-4,-6) in slope intercept form is:</u></em>

<em><u>Solution:</u></em>
Given that we have to write the equation of the line passing through the point (-4,-6) that is parallel to the line y=-2/9x-1
<em><u>The equation of line in slope intercept form is given as:</u></em>
y = mx + c ---------- eqn 1
Where, "m" is the slope of line and "c" is the y intercept
<em><u>Given equation of line is:</u></em>

<em><u>On comparing the above equation with eqn 1,</u></em>

We know that slopes of parallel lines are equal
Thus slope of line parallel to given line is also 
Now find the equation of line with slope
and passing through (-4, -6)


Thus the equation of line is found
Well by the looks of it The missing angle is 70 degrees. I say this because 110 + 70 = 180. If you were asking what were the two angles just divide.
Step-by-step explanation:
The solution is in the image
Find 5 points by plugging in Xs for y=2x-3
0 ---> -3
1 ----> -1
2 ---> 1
3 ---> 3
4 ---> 5
then graph the points. X is the first number, and how far you go along the horizontal axis. Y is the second number, and determines how far you go along the vertical axis.