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3 years ago

Please help and explain how to do this I don't understand it thank you

Mathematics

2 answers:

n200080 [17]3 years ago

8 0

Answer:

The table says it was angle 31 so then you would go to angle and go across the line to where it says cos then you right the number which would be 0.8572.

Mazyrski [523]3 years ago

5 0

You just have to look at the table that give you it was angle 31 so then you would go to angle and go across the line to where it says cos then you right the number which would be 0.8572

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QveST [7]

Answer:

A. 72

Step-by-step explanation:

If she is making 12 cobblers and needs 6 peaches per one.

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KonstantinChe [14]

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Vladimir [108]

Answer:

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3 years ago

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alexira [117]

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Consider the function on the interval (0, 2π). f(x) = 7 sin2(x) + 7 sin(x) (a) Find the open interval(s) on which the function i

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Answer with Step-by-step explanation:

Given

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$f'(x)>0\\\\14cos(2x)+7cos(x)>0\\\\2cos(2x)+cos(x)>0\\\\2(2cos^{2}(x)-1)+cos(x)>0\\\\4cos^{2}(x)+cos(x)-2>0\\\\(2cos(x)+\frac{1}{2})^2-2-\frac{1}{4}>0\\\\(2cos(x)+\frac{1}{2})^2>\frac{9}{4}\\\\2cos(x)>\frac{3}{2}-\frac{1}{2}\\\\\therefore cos(x)>\frac{1}{4}\\\\\therefore x=[0,cos^{-1}(1/4)]\cup [2\pi-cos^{-1}(1/4),2\pi ]$

Similarly for decreasing function we have

$[tex]f'(x)$

Part b)

To find the extreme points we equate the derivative with 0

$f'(x)=0\\\\cos(x)=\frac{1}{4}\\\\x=cos^{-1}(\frac{1}{4})$

Thus point of extrema is only 1.

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4 years ago