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ANTONII [103]
3 years ago
6

A⁴+b⁴=a²b² ,prove that a⁶+b⁶=0

Mathematics
1 answer:
Mekhanik [1.2K]3 years ago
7 0
a^4+b^4=a^2b^2\\
a^4-a^2b^2+b^4=0\\
a^4-2a^2b^2+b^4+a^2b^2=0\\
(a^2+b^2)^2=-a^2b^2

The only possible option is that a^2+b^2=0 \wedge a^2b^2=0\\ and this condition is met only when a=0 \wedge b=0.

0^6+0^6=0\\
0=0
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Find the inverse function (find f^-1)
Reil [10]

Step-by-step explanation:

f(x) = (x-2)/(3x+3). Let y = f(x).

Then y = (x-2)/(3x+3).

y(3x+3) = x - 2

3xy + 3y = x - 2

3xy - x = -3y - 2

x(3y-1) = -(3y+2)

x = -(3y+2)/(3y-1)

Hence, the inverse of f(x) is -(3x+2)/(3x-1).

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3 years ago
SOMEONE PLEASE JUST ANSWER THIS FOR BRAINLIEST!!!
svet-max [94.6K]

Remember to be mindful of signs when adding and subtracting. 2c^2+5c+4

3 0
3 years ago
Find the Relative Change in the values of the function f(x) = x3 + 2 between x = 1 and x = 2.5 Enter your answer accurate to thr
ehidna [41]

Answer:

9.750

Step-by-step explanation:

formula for average rate of change is ;

f(b)- f(a)/b- a

here a = 1 and b = 2.5

f(b) = (2.5)^3 + 2 = 17.625

f(a) = 1^3+ 2 = 3

using the formula above, we have it that

(17.625-3)/2.5-1 = 9.750

4 0
3 years ago
If someone help me that be awesome
nevsk [136]
The answer is 12,600,000... hope this helps any :3
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4 years ago
Read 2 more answers
Could someone please help on this question? I’m giving 20 points and brainliest but I need it quickly so please help!
AnnZ [28]
<h3>Answer:  HF = 5</h3>

=============================================

Explanation:

Refer to the diagram below. I'm adding in points A and B, which are marked in blue. I'm also adding in variables x, y, and z.

The goal is to find HF, so let's make that equal to x. This is also equal to HB because they are radii of the same circle.

Let y be the length of segments JA and JB.

Let z be the length of segments CF and CA.

So in short we have

  • x = HF = HB
  • y = JA = JB
  • z = CF = CA

We know that

  • CH = 13
  • HJ = 19
  • CJ = 22

This must mean

  • CH = CF+HF = z+x = 13
  • HJ = HB+JB = x+y = 19
  • CJ = CA+JA = z+y = 22

Or in short,

  • z+x = 13
  • x+y = 19
  • z+y = 22

Let's solve the first equation for z to get z = -x+13. I subtracted x from both sides.

Now plug this into the third equation to get

z+y = 22

(z) + y = 22

(-x+13) + y = 22 ... replace z with -x+13

-x+13+y = 22

-x+y+13 = 22

-x+y = 22-13 .... subtract 13 from both sides

-x+y = 9

------------------------------------

So we have this reduced system of equations of two variables and two equations

  • x+y = 19 ... found earlier
  • -x+y = 9 .... what we just found above

Add the equations straight down. This is the elimination property.

Doing so leads to the x terms canceling out since x + (-x) = 0x = 0

The y terms add to y+y = 2y

The terms on the right hand side add to 19+9 = 28

We are left with 2y = 28 which solves to y = 28/2 = 14.

If y = 14, then,

x+y = 19

x+14 = 19

x = 19-14

x  = 5

In which we can then say

z = -x+13

z = -5+13

z = 8

Though we don't need to find z (unless you're curious about it).

Since x = 5, and we set HF equal to x, this means that HF = 5.

6 0
3 years ago
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