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Usimov [2.4K]
3 years ago
6

Could someone please help on this question? I’m giving 20 points and brainliest but I need it quickly so please help!

Mathematics
1 answer:
AnnZ [28]3 years ago
6 0
<h3>Answer:  HF = 5</h3>

=============================================

Explanation:

Refer to the diagram below. I'm adding in points A and B, which are marked in blue. I'm also adding in variables x, y, and z.

The goal is to find HF, so let's make that equal to x. This is also equal to HB because they are radii of the same circle.

Let y be the length of segments JA and JB.

Let z be the length of segments CF and CA.

So in short we have

  • x = HF = HB
  • y = JA = JB
  • z = CF = CA

We know that

  • CH = 13
  • HJ = 19
  • CJ = 22

This must mean

  • CH = CF+HF = z+x = 13
  • HJ = HB+JB = x+y = 19
  • CJ = CA+JA = z+y = 22

Or in short,

  • z+x = 13
  • x+y = 19
  • z+y = 22

Let's solve the first equation for z to get z = -x+13. I subtracted x from both sides.

Now plug this into the third equation to get

z+y = 22

(z) + y = 22

(-x+13) + y = 22 ... replace z with -x+13

-x+13+y = 22

-x+y+13 = 22

-x+y = 22-13 .... subtract 13 from both sides

-x+y = 9

------------------------------------

So we have this reduced system of equations of two variables and two equations

  • x+y = 19 ... found earlier
  • -x+y = 9 .... what we just found above

Add the equations straight down. This is the elimination property.

Doing so leads to the x terms canceling out since x + (-x) = 0x = 0

The y terms add to y+y = 2y

The terms on the right hand side add to 19+9 = 28

We are left with 2y = 28 which solves to y = 28/2 = 14.

If y = 14, then,

x+y = 19

x+14 = 19

x = 19-14

x  = 5

In which we can then say

z = -x+13

z = -5+13

z = 8

Though we don't need to find z (unless you're curious about it).

Since x = 5, and we set HF equal to x, this means that HF = 5.

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1/60

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3 years ago
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PLEASE HELP ME!!!!!!!!
GREYUIT [131]

Answer:

  The solution to the system of equations (x, y) = (2, 4) represents the month in which exports and imports were equal. Both were 4 in February.

Step-by-step explanation:

We're not sure what "system of equations" is being referenced here, since no equations are shown or described.

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Perhaps your "system of equations" is ...

  f(x) = some equation

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Then the solution to this system of equation is the pair of values (x, y) that gives ...

  y = f(x) = g(x)

If x represents the month number, then the solution can be read from the table:

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This is the month in which exports and imports were equal. Both numbers were 4 in February.

7 0
3 years ago
Isabella's rain gauge showed 3 centimeters/cra) last Tuesday. This Tuesday,
Llana [10]
<h3><u>Question:</u></h3>

Isabella’s rain gauge showed 3 4/5 centimeters (cm) last Tuesday. This Tuesday,  the rain gauge showed 5 7/10  centimeters. How many more centimeters of rain  fell during the week?

A 9 1/2cm B 8 1/2cm c 2 4/5cm D 1 9/10 cm​

<h3><u>Answer:</u></h3>

Option D

1\frac{9}{10}  more centimeters of rain  fell during this week than last week

<h3><u>Solution:</u></h3>

From given,

Last\ tuesday = 3\frac{4}{5}\ cm\\\\Convert\ to\ improper\ fraction\\\\Last\ tuesday = \frac{5 \times 3 + 4}{5} = \frac{19}{5}\ cm

Also given that,

This\ tuesday = 5\frac{7}{10}\ cm = \frac{10 \times 5 + 7}{10} = \frac{57}{10}\ cm

<em><u>How many more centimeters of rain  fell during the week?</u></em>

This\ tuesday - last\ tuesday = \frac{57}{10} - \frac{19}{5}\\\\This\ tuesday - last\ tuesday = \frac{57}{10} - \frac{19 \times 2}{5 \times 2}\\\\This\ tuesday - last\ tuesday = \frac{57-38}{10}\\\\This\ tuesday - last\ tuesday = \frac{19}{10}\\\\Converting\ to\ mixed\ fraction\\\\\rightarrow \frac{19}{10} = 1\frac{9}{10}

Thus 1\frac{9}{10}  more centimeters of rain  fell during this week than last week

8 0
3 years ago
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GuDViN [60]

Answer:

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Step-by-step explanation:

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8 0
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How is breaking apart the problem 16x34 like solving four simpler problems?
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The four problems can be written as 16*2*17, then 32*17, then 32*(10+7), then 320+224
3 0
3 years ago
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