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frosja888 [35]
3 years ago
10

Katherine is landscaping her home with juniper trees and pansies. She wants to arrange 15 pansies around each of 8 trees. Each t

ree costs $20.75 and a six-pack of pansies costs $2.50. Explain how to write an expression to find Katherine’s final cost.
Mathematics
2 answers:
Doss [256]3 years ago
5 0
Let
X-----------------> number of pansies
y-----------------> number of trees

we know that
x=15*8----------> x=120 pansies
y=8 trees

cost of each trees is----------> $<span>20.75
</span>cost of each pansies is------> $2.50/6------> $5/12

[<span>expression to find Katherine’s final cost]=[cost trees]+[cost pansies]
</span>[cost trees]=y*$20.75
[cost pansies]=x*($5/12)   

[expression to find Katherine’s final cost]=y*($20.75)+x*($5/12)
[expression to find Katherine’s final cost]=8*($20.75)+120*($5/12)

[expression to find Katherine’s final cost]=$166+$50
[expression to find Katherine’s final cost]=$216

the answer is 
[expression to find Katherine’s final cost]=y*($20.75)+x*($5/12)
[expression to find Katherine’s final cost]=8*($20.75)+120*($5/12)

Katherine’s final cost is $216
Arlecino [84]3 years ago
4 0

Answer:

Add the cost of pansies to 15 and the cost of trees to 8. Then add them together.

Step-by-step explanation:

That's what I said and I got it correct so there you go, hope this helps.

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Evaluate |bc|, given a = 5, b = -3, and c = -2.
Anni [7]

Answer:

6

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
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<u>Algebra I</u>

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Step-by-step explanation:

<u>Step 1: Define</u>

|bc|

a = 5

b = -3

c = -2

<u>Step 2: Evaluate</u>

  1. Substitute:                    |-3 · -2|
  2. Multiply:                        |6|
  3. Evaluate:                       6
7 0
2 years ago
What is the probability that at least one of a pair of fair dice lands of 5, given that the sum of the dice is 8?
o-na [289]

Answer:

0.40

Step-by-step explanation:

to find out the probability that at least one of a pair of fair dice lands of 5, given that the sum of the dice is 8

Let A = sum of dice is 8

B = one lands in 5

P(B/A) = P(AB)/P(A) by conditional probability

P(AB) = sum is 8 and one is 5

So (5,3) or (3,5)

P(A) = sum  is 8.

i.e. (2,6) (2,6) (3,5) (5,3) (4,4)

Required probability

= n(AB)/n(A)

=\frac{2}{5} =0.40

4 0
3 years ago
The first element in an arithmetic sequence is 2. Its twenty second is 14. Find the value of n so that a(n)=6
Aleks04 [339]

Answer:

<h2>n = 8</h2>

Step-by-step explanation:

Given the nth term of an arithmetic sequence to be Tn = a+(n-1)d

a = first term of the sequence

n = number of terms

d = common difference.

Given the first element a = 2 and 22nd to be 14

T22 = a+(22-1)d = 14

a+21d = 14

Substtuting a = 2 into the equation to get d

2+21d = 14

21d = 12

d = 12/21

d = 4/7

The nth term of the sequence given a = 2 and d = 4/7 will be expressed as;

Tn = 2+(n-1)4/7

Given Tn = 6

6 = 2+(n-1)4/7

6 = 2+4/7 n - 4/7

6-2+4/7 = 4/7 n

32/7=4/7 n

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8 0
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Answer:

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Step-by-step explanation:

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Answer:

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4/5*2.5 = 10/5 = 2

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Step-by-step explanation:

3 0
2 years ago
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