11 is 20% of what number?

1 answer:

4 0

I think its 55 because 11 divided by .2 (20%) equals 55 then if you wanna check it then multiply 55 with .2 and you'd get 11.

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Please help and thank you!

lukranit [14]

9514 1404 393

Answer:

base area: 21 ft²
volume 105 ft³

Step-by-step explanation:

The area of a triangle is given by the formula ...

A = (1/2)bh

The base and height of a right triangle can be taken to be the leg lengths, since each is perpendicular to the other.

A = (1/2)(6 ft)(7 ft) = 21 ft² . . . . base area

The volume is the product of the base area and the height:

V = Bh

V = (21 ft²)(5 ft) = 105 ft³ . . . . volume

6 0

3 years ago

Write out the sample space for the given experiment. Use the following letters to indicate each choice: M for mushrooms, A for a

MrMuchimi

Answer: {(MBV), (MBH) , (MEV) , (MEH) , (OBV), (OBH) , (OEV) , (OEH)}

Step-by-step explanation:

Sample space is a set that contains all the possible outcomes for an event.

For salad:

Choices for extra toppings (mushrooms, olives) =2

Choices for meats (bacon, eggs) =2

Choices for dressings (vinaigrette, honey mustard.)= 2

By Fundamental counting principal .

The number of different salads can be made= (Choices for extra toppings) x (Choices for meats ) x (Choices for dressings)

= 2 x 2 x 2 = 8

All the possible outcomes = (MBV), (MBH) , (MEV) , (MEH) , (OBV), (OBH) , (OEV) , (OEH)

Required Sample space would be : {(MBV), (MBH) , (MEV) , (MEH) , (OBV), (OBH) , (OEV) , (OEH)}

5 0

2 years ago

A restaurant has an electronic system that randomly selects customers when they pay for their meal to

polet [3.4K]

Using the binomial distribution, it is found that there is a 0.81 = 81% probability that NEITHER customer is selected to receive a coupon.

For each customer, there are only two possible outcomes, either they receive the coupon, or they do not. The probability of a customer receiving the coupon is independent of any other customer, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$