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![\boxed{\boxed{\sf\sqrt[10]{y}}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cboxed%7B%5Csf%5Csqrt%5B10%5D%7By%7D%7D%7D)
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<h3>1.) Solve
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<em> - So this means from the choices, </em>![\sqrt[10]{y}=\sqrt[10]{y}](https://tex.z-dn.net/?f=%5Csqrt%5B10%5D%7By%7D%3D%5Csqrt%5B10%5D%7By%7D)
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Answer: Hello there!
initially Maria has 6 red marbles, 6 blue marbles, and 4 green marbles.
You know that in the first pick, Maria gets a green marble ( this means that now there are 3 green marbles left)
Now we want to know the probability that she gets a red marble on the second pick.
Now there are 6 + 6 + 3 = 15 marbles in the bag, and 6 of them are red ones. Then the probability of getting one red is the number of red ones divided by the total amount ( which is the ratio of red marbles to total marbles)
this is 6/15.
now you can see that there is no 6/15 in the options, so we need to see which one is equivalent.
if we took the option C, 2/5, and multiply both denominator and numerator by 3, we get (3*2)/(3*5) = 6/15, then 2/5 and 6/15 are equivalents.
Then the correct answer is C.
Step-by-step explanation:
Answer:
B) restaurant to the skating rink
C) (3,2)
Step-by-step explanation:
B) restaurant to the skating rink
C) (3,2)
Midpoint = (x1 + x2) / 2, (y1 + y2)/2
(-2,1)....x1 = -2 and y1 = 1
(4,-1)...x2 = 4 and y2 = -1
time to sub
m = (-2 + 4) / 2 , (1 + (-1) / 2
m = (2/2), (0/2)
m = (1,0) <==
y = -x + 1.....(1,0)...x = 1 and y = 0
0 = -1 + 1
0 = 0 (correct)
so the midpoint M (1,0) lies on the line since its coordinates satisfy the equation <===
