Ask question

Ask question

All categories

2 years ago

13

Given the initial point (2, 3), which other three points would make an isosceles trapezoid on the coordinate plane?

1 answer:

Mashutka [201]2 years ago

8 0

Answer:

If it's an isosceles triangle the non parallel sides should be equal

It will be satisfied only when the coordinates of the other 3 points are (4,6), (6,6), (8,3)

The answer is C.

Hope this helps!

You might be interested in

• To round a number, look at the digit to the right of the

nadya68 [22]

Answer:

2. A) 37 B)160 C) 110

The tens digit is 10,20,30,40,50,60,70,80,90. Two away to the left of a decimal point.

3. A)730 B) 675 C)1930

The hundreds digit is three from the left of a decimal point.

4. A) 0.40 B)74.60 C)15.20

The tenth is one away to the right of the decimal.

5. A)1.210 B) 3.430 C)0.350

The hundreth is two away to the right of the decimal point.

Explanation:

If it is above 5 you bring the digit before it up by one, if it is under 5 you bring the digit that is under 5 to zero.

8 0

2 years ago

Help asap my last question GIVING BRAINLIST!!!!

Alex

Answer:

1) $x < 0$

2) $x > 0$

3) $x < 10$

4) $x < -\frac{31}{55}$

5) $x \geq 0$

6) $x \geq -1$

Step-by-step explanation:

1) $-3 > 2x -3$

$2x- 3 < -3$

$2x - 3 + 3 < -3 +3$

$2x < 0$

$\frac{2x}{2} < \frac{0}{2}$

$x < 0$

2) $5 > -x + 5$

$-x + 5 < 5$

$- x + 5 -5 < 5 - 5$

$-x < 0$

$\frac{-x}{-1} < \frac{0}{-1}$

$x > 0$

3) $\frac{x}{5} -2 < 0$

$5 \times (\frac{x}{5} - 2 ) \times 5 < 0$

$x - 10 < 0$

$x -10 + 10 < 0 +10$

$x < 10$

4) $-5x + 11 > 31$

$-5x \cdot 11 < 31$

$-55x < 31$

$\frac{-55x}{-55} > \frac{31}{-55}$

$x < -\frac{31}{55}$

5) $\frac{1}{2}x - 4 \geq -4$

$\frac{1}{2}x -4 +4 \geq -4 +4$

$\frac{1}{2}x \geq 0$

$\frac{\frac{1}{2}x }{\frac{1}{2} } \geq \frac{0}{\frac{1}{2} }$

$x \geq 0$

6) $-4x + 2 \leq 6$

$-4x +2 - 2 \leq 6 -2$

$-4x < 4$

$\frac{-4x}{-4} \leq \frac{4}{-4}$

$x \geq -1$

6 0

3 years ago

Identify the type of conic section that is represented by the equation y^2- 1 = 4(x-7). DUE IN 2 HOURS, will give BRAINLIEST! A.

Elenna [48]

Answer:

Solution : Parabola

Step-by-step explanation:

As you can see only one variable is square in this situation, so it can only be a parabola. We can prove that it is a parabola however by converting it into standard form (x - h)^2 + (y - k)^2.

$y^2-1=4\left(x-7\right) = y^2-1=4\left(x-7\right)$

Respectively it's properties would be as follows,

$\left(h,\:k\right)=\left(\frac{27}{4},\:0\right),\:p=1$

8 0

2 years ago

Find the missing lengths m and n in the rectangular prism.

Sav [38]

Answer:

where is the picture???

what are the given lengths?

4 0

2 years ago

Solve for x 2|x-6|+14=38

ale4655 [162]

Answer:

x=18 x=-6

Step-by-step explanation:

2|x-6|+14=38

The first step is to isolate the absolute value

Subtract 14 from each side

2|x-6|+14-14=38-14

2|x-6|=24

Divide by 2 on each side

2/2|x-6|=24/2

|x-6| = 12

Now we can seperate the absolute value into two parts, the positive and the negative

x-6 =12 x-6 = -12

Add 6 to each side

x-6+6 =12+6 x-6+6 = -12+6

x=18 x= -6

4 0

3 years ago