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sergey [27]
3 years ago
7

A bowl contains 4 yellow marbles and 3 red marbles. Eric randomly draws 3 marbles from the bowl. He replaces each marble after i

t is drawn. What is the probability that he draws 1 yellow marble and 2 red marbles
Mathematics
2 answers:
Slav-nsk [51]3 years ago
7 0
First draw p yellow = 4/7
2nd draw p red = 3/7
3rd draw p red = 3/7

To find the probability of this event (1yellow 2 red - with replacement) we multiply the probabilities.

4/7 x 3/7 x3/7  = 36/343 which cannot be reduced further
Rasek [7]3 years ago
6 0

There are 7 marbles in the bowl all together.

-- Probability of a yellow marble on any draw  =  4/7
-- Probability of a red marble on any draw       =  3/7

-- Probability of one yellow and two red in 3 draws = (4/7) (3/7) (3/7) = <u>36/343</u>

                                                                                     =    <em>10.5%  </em>(rounded)

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