1. X+18
2. Y-5
3. x+7=y
4. Y-10
5. 7-x
16. r-s
17. R+25
18. z-12
19. m+9
20. Y-11
We're not given the choices but we don't need them.
The only way this problem is tractable to a middle or high schooler is if the polynomial is perfect cube; a little thought yields

To find the inverse let's call f(x) x and call x y and solve for y.

![y-2 = \sqrt[3]{x}](https://tex.z-dn.net/?f=y-2%20%3D%20%5Csqrt%5B3%5D%7Bx%7D)
![y = 2 + \sqrt[3]{x}](https://tex.z-dn.net/?f=y%20%3D%202%20%2B%20%5Csqrt%5B3%5D%7Bx%7D)

Plug in x = 2:

Multiply:

Subtract 4 to both sides:

Divide 3 to both sides:

So our solution is
In accordance with Pythagoras theorem ,
7^2 + 13^2 = x^2
49 + 169 = x^2
218 = x^2
√(218) = x
14.764 = x
.
Could u please manage with the triplet ..
.
Sorry abt that
Answer:
1≤x≤5
Step-by-step explanation:
The domain is the values that x can take
X goes from 1 to 5
1≤x≤5