S = 2J - 1
R = J + 53
S - 25 = J + 25...S = J + 50
2J - 1 = J + 50
2J - J = 50 + 1
J = 51 <===Jason has 51 CD's
R = J + 53
R = 51 + 53
R = 104 <===Raoul has 104 CD's
S = 2J - 51
S = 2(51) - 1
S = 102 - 1
S = 101 <===Seth has 101 CD's
Answer:
Step-by-step explanation:
Simplify the expression.
2x^3-10x^2+22x-14
Start with the equation of a circle whose center is at (h,k) and whose radius is r:
(x-h)^2 + (y-k)^2 = r^2
Substituting the given coordinates of the center:
(x-5)^2 + (y-[-5])^2 = r^2, or (x-5)^2 + (y+5)^2 = r^2
Substituding the given coordinates of a point (6,-2) on the circle:
(6-5)^2 + (-2+5)^2 = r^2
Simplifying:
1^2 + 3^2 = r^2, or 1 + 9 = r^2, or 10= r^2. Then r = sqrt(10).
