Given that the sequence is:
1,2,4,8,32
the recursive formula will be found as follows:
first term is=1
the sequence can be written as:
1,2,4,8,32
=(1*2^0),(1*2^1),(1*2^2),(1*2^3),(1*2^4)
thus the recursive formula will be
an=a1(r)^(n-1)
plugging the values we get:
an=1(2)^(n-1)
We know that
[area of a circle ]=pi*r²
diameter=4 in
r=4 in/2-----> 2 in
so
area=pi*2²-----> area of the circle=4*pi in²
the answer is
the area, in square inches, of the circle is <span>3.14 • 2²</span>
Answer:
D) 4 1/2
Step-by-step explanation:
Hope that helps :)
You don't provide the instructions for this problem, leaving it up to me to guess what you might want.
Note that g(x) should be written as g(x) = (x-2)^2, whereas f(x) = g(x) + 3 (as presented).
If we let g(x) be the input to f(x), we get the "composition" of g and f:
f(x) = g(x) + 3 = (x-2)^2 + 3. You could leave the answer as is or you could expand (x-2)^2: f(x) = x^2 - 4x + 4 + 3 (and so on).
A relation is a function, if and only if, the x- values do not repeat in a given set.
