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allsm [11]
3 years ago
14

What is the vertical height, h?

Mathematics
1 answer:
bixtya [17]3 years ago
8 0

Answer:

<h2>             6.2</h2>

Step-by-step explanation:

s = 10 so ¹/₂s = 5

Pythagorean theorem:

h^2+(\frac12s)^2=8^2\\\\h^2+5^2=8^2\\\\h^2=64-25\\\\h^2=39\\\\h=\sqrt{39}=6.2449979....\approx6.2

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Share 270g in the ratio 5 : 4
Phantasy [73]

Answer:

150:120

Step-by-step explanation:

U add the 2 ratios 5+4=9

270/9=30

30*5=150

30*4=120

8 0
3 years ago
A price decreased from 60$ to 45$ find the percent of decrease
BlackZzzverrR [31]
Percent change = [(45 - 60) / 60] x 100 = -25 % (decrease)
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3 years ago
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A home is to be built on a 56 foot 9 inch wide lot. The house is 5 feet 5 inches from the side of the lot and is 34 feet 10 inch
daser333 [38]
<span>Total lot - house -other side
=(56 ft 9 in) - (34 ft 10 in) - (5 ft 5 in)
=(55 ft 21 in) - (34 ft 10 in) - (5 ft 5 in)
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Convert to inches: </span>16 ft x 12 in/ft)+ 6 in= Total in inches<span>192 in + 6 in= Total in inches
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8 0
3 years ago
How do I go about solving (27x^3/8y^9)^5/3? And what is the role of the numerator and denominator?
MrRissso [65]
\left( \frac{27x^3}{8y^9}\right)^ \frac{5}{3}  \\\\\\ =\left( \frac{(3x)^3}{(2y^3)^3}\right)^ \frac{5}{3} \\\\\\ =  \frac{(3x)^{3 \times  \frac{5}{3} }}{(2y^3)^{3 \times  \frac{5}{3} }} \\\\\\ =\frac{(3x)^5}{(2y^3)^{5 }} \\\\\\ =\frac{243x^5}{32y^{15}}

Now, If the exponent was negative like you asked....

\left( \frac{27x^3}{8y^9}\right)^ {-\frac{5}{3}} \\\\\\ =\left( \frac{8y^9}{27x^3}\right)^ {\frac{5}{3}}\\\\\\ =\left( \frac{(2y^3)^3}{(3x)^3}\right)^ \frac{5}{3} \\\\\\ = \frac{(2y^3)^{3 \times \frac{5}{3} }}{(3x)^{3 \times \frac{5}{3} }} \\\\\\ =\frac{(2y^3)^{5 }}{(3x)^5} \\\\\\ =\frac{32y^{15}}{243x^5}

5 0
3 years ago
You earned $210 over 3 years on an account with a 7% interest rate. What was your initial deposit (principal)?
AveGali [126]

Answer:

3,000$

Step-by-step explanation:

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3 years ago
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