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2 years ago

Evaluate 2/ 3 ÷ 4 /5 Give your answer as a fraction in its simplest form.

Mathematics

1 answer:

gulaghasi [49]2 years ago

7 0

Step-by-step explanation:

Our problem:

$\frac{2}{3} \div \frac{4}{5} = unknown$

How to solve?

Find the reciprocal (opposite) of 4/5, then multiply. Simplify if necessary.

Find the reciprocal:

$\frac{2}{3} \times \frac{5}{4} = unknown$

Multiply:

$\frac{2}{3} \times \frac{5}{4} = \frac{10}{12}$

Simplify:

$\frac{10 \div 2}{12 \div 2} = \frac{5}{6}$

5/6 is your answer.

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Ross has to fill up a 300 gallon tank. There are already 75

stepan [7]

Answer: He needs 9 hours to finish the task.

Step-by-step explanation:

Hi, first we have to subtract the gallons of water already in the tank (75) to the total capacity of the tank (300).

300-75 = 225

He needs to fill 225 gallons.

Since the pump Ross uses can fill 25 gallons of water per hour, the proportion is :

25 g / 1h

For 225 gallons:

225 g / x hours

Solving for x

25/1 = 225/x

x= 225/ (25/1)

x = 9 hours

5 0

3 years ago

Fill in the blanks below to make a true statement. In a binomial experiment with n trials and probability of success p, if np (1

Sergeu [11.5K]

Answer:

$\mu_{x}=np$

$\sigma^2_{X}=np(1-p)$

Step-by-step explanation:

∵ When x is a random variable having distribution B(n, p), then for sufficiently large value of n, the following random variable has a standard normal distribution,

$\frac{x-\mu}{\sigma}\sim N(0,1)$

Where,

$\mu=np$

$\sigma^2=np(1-p)$

Here the variable X has a binomial distribution,

Such that, np (1 - p) ≥ 10 ⇒ n is sufficiently large.

Where, n is the total numbers of trials, p is success in each trials,

So, the mean of variable X is,

$\mu_{X} = np$

And, variance of variable X is,

$\sigma^2{X}=np(1-p)$

3 0

3 years ago

Please help in really stuck

sattari [20]

$\int\limits {\pi y^2} \, dy$

y = 2 + x^6

y - 2 = x^6

x = (y - 2)^1/6

$\pi \int\limits^3_2 {(y - 2)^{1/6}} \, dx$

Well, solving this integral

$\pi \int\limits^3_2 {(y - 2)^{1/6}} \, dx$ = 2,69279

6 0

3 years ago

Look at the problems 2.3×3.68 and 23×368. How are they similar? Which problem has a greater product?

Margarita [4]

Here is your answer:

1. These equations are similar because they "both share the same numbers but one is a decimal and the other is a whole number."

2. You have to solve each equation in order to determine which number is greater:

$2.3\times 3.68$
$2.3 \times 3.68 = 8.464$
$= 8.464$

And:

$23 \times 368 =$
$23 \times 368 = 8464$
$= 8464$

Finally:

$8.464 < 8464$

Therefore "8,464 is greater than 8.464."

Hope this helps!

3 0

3 years ago

A cylinder and sphere have the same height. If the sphere has a volume of 361 cubic units, what is the height of the cylinder?

dalvyx [7]

Answer:

Sa = 36 circumference per meter square

3 0

2 years ago

Read 2 more answers