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Rudiy27
3 years ago
12

What is 5/6 converted unit minutes??!?!?!?!???????

Mathematics
1 answer:
kykrilka [37]3 years ago
5 0
5/6 converged into minutes would be 50 minutes. You can figure this out by dividing an hour (60 minutes) by 6 which is 10. Then you multiply 10 by 5 to get a final answer of 50 minutes.
I hope this helped! :-)
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What is the volume of the pyramid to the nearest whole unit?
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Answer:

Step-by-step explanation:

V= lwh/3

V= ((6)(11)(6))/3

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A) Show that the equation 20-x^3-7x^2=0 can be rearranged to give x=20/x^2 - 7
AVprozaik [17]

Answer:

Step-by-step explanation:

      20-x^3-7x^2=0

a)

  • Add x^3 to both sides of the equation:     20-7x^2=x^3
  • Divide both sides by x^2:    \frac{20}{x^2} -\frac{7x^2}{x^2} =\frac{x^3}{x^2}  ⇒  \frac{20}{x^2} -7 =x

b)

    x_1=\frac{20}{(x_0)^2} -7

⇒ x_1=\frac{20}{(-9)^2} -7

⇒ x_1=-\frac{547}{81}

    x_2=\frac{20}{(x_1)^2} -7

⇒ x_2=\frac{20}{(-\frac{547}{81})^2} -7

⇒ x_2=-6.561443673...

   x_3=\frac{20}{(x_2)^2} -7

⇒ x_3=\frac{20}{(-6.561443673...)^2} -7

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c) approximation to the location of one of the roots of the equation.  Each iteration gives a slightly more accurate value of a root x.

4 0
3 years ago
Perform the indicated operation. Be sure the answer is reduced.
avanturin [10]
<h3>Given Equation:-</h3>

\boxed{ \rm  \frac{4x^{2}y^{3}z}{9} \times  \frac{45y}{8 {x}^{5} {z}^{5} }}

<h3>Step by step expansion:</h3>

\dashrightarrow \sf\dfrac{4x^{2}y^{3}z}{9} \times  \dfrac{45y}{8 {x}^{5} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{ \cancel4x^{2}y^{3}z}{9} \times  \dfrac{45y}{ \cancel8 {x}^{5} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{9} \times  \dfrac{45y}{2{x}^{5} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{ \cancel9} \times  \dfrac{ \cancel{45}y}{2{x}^{5} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{1} \times  \dfrac{5y}{2{x}^{5} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{x^{0}y^{3}z}{1} \times  \dfrac{5y}{2{x}^{5 - 2} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{y^{3}z}{1} \times  \dfrac{5y}{2{x}^{3} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{y^{3}z {}^{0} }{1} \times  \dfrac{5y}{2{x}^{3} {z}^{3 - 1} }

\\  \\

\dashrightarrow \sf\dfrac{y^{3}}{1} \times  \dfrac{5y}{2{x}^{3} {z}^{2} }

\\  \\

\dashrightarrow \sf  \dfrac{5y \times  {y}^{3} }{2{x}^{3} {z}^{2} }

\\  \\

\dashrightarrow \sf  \dfrac{5y {}^{0}  \times  {y}^{3 + 1} }{2{x}^{3} {z}^{2} }

\\  \\

\dashrightarrow \sf  \dfrac{5 \times  {y}^{4} }{2{x}^{3} {z}^{2} }

\\  \\

\dashrightarrow \bf  \dfrac{5 {y}^{4} }{2{x}^{3} {z}^{2} }

\\  \\

\therefore \underline{ \textbf{ \textsf{option \red c \: is \: correct}}}

8 0
2 years ago
I don’t know how to complete this problem. Can anyone help out? Please and thank you :)
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