To find the x-int., let y = 0 and solve for x: 13x = 6, so x = 6/13: (6/13, 0)
To find the y-int., let x =0 and read off the y-int: (0, -6)
Answer:
1. is a 30 60 90 triangle so x = 30
pardon my bad handwriting for below
2.
STEP 1: subtract the angle you have from 180
STEP 2: add your x values together, if there is a non x number (such as + 10) balance it out on the other side by adding or subtracting
STEP 3: divide so that x has no coeffecient in front of it
STEP 4: substitute x values with the value you got
STEP 5: verify by adding the angles you got, it'll be correct if it equals 180
Answer: Period: 4. Amplitude: 3
Step-by-step explanation: The period is how long it takes for one cycle of the function (one up and down). In this graph, one cycle ends at 4.
The amplitude is how far away the extremes of the graph are from the midline. This graph is a total of 6 units tall, making the amplitude 3. (I usually find total graph height and divide by 2.)
The given quadrilateral ABCD is a parallelogram since the opposite sides are of same length AB and DC is 4 and AD and BC is 2.
<u>Step-by-step explanation</u>:
ABCD is a quadrilateral with their opposite sides are congruent (equal).
The both pairs of opposite sides are given as AB = 3 + x
, DC = 4x
, AD = y + 1
, BC = 2y.
- AB and DC are opposite sides and have same measure of length.
- AD and BC are opposite sides and have same measure of length.
<u>To find the length of AB and DC :</u>
AB = DC
3 + x = 4x
Keep x terms on one side and constant on other side.
3 = 4x - x
3 = 3x
x = 1
Substiute x=1 in AB and DC,
AB = 3+1 = 4
DC = 4(1) = 4
<u>To find the length of AD and BC :</u>
AD = BC
y + 1 = 2y
Keep y terms on one side and constant on other side.
2y-y = 1
y = 1
Substiute y=1 in AD and BC,
AD = 1+1 = 2
BC = 2(1) = 2
Therefore, the opposite sides are of same length AB and DC is 4 and AD and BC is 2. The given quadrilateral ABCD is a parallelogram.
The shape consists of 5 faces. One on the front, one on the back, one on the left of the shape, the other on the right, and of course the one on the bottom :)
Hope it helped.
