Answer:
Interval for t statistic = (-1.345, 1.345)
Step-by-step explanation:
given that a random sample of size 15 is selected from a normal population. The population standard deviation is unknown.
Since population std deviation is unknown and also sample size <30, we have to use t test only for testing of hypothesis
Given it is a two tailed test at 10% significance level.
Degree of freedom = 15-1 =14
t critical value for df 14 two tailed is
1.345
Hence our test statistic should lie between
(-1.345, 1.345)
Then null hypothesis is accepted
Other wise it is rejected.
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➷ 5 + 3 + 3 + 4 = 15
5/15 * 5/15 = 25/225
This can be simplified to 1/9
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Answer:
ohhh sweet..................
Answer:
.44 pounds of sugar are used in each cake
Step-by-step explanation:
Just divide 440 by 1,000