Factoriza 4x²-y²-6y-9
2 answers:
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In terms of the trigonometric ratios for ΔABD, what is the length of line segment BD?
Answer:
Step-by-step explanation:
∆ABD is a right triangle.
Recall: trigonometric ratios of any right triangle can easily be understood or remembered with the acronym, SOHCAHTOA.
SOH => sin(θ) = opposite/hypotenuse
CAH => Cos(θ) = adjacent/hypotenuse
TOA = tan(θ) = opposite/adjacent
Thus, the length of segment BD, in terms of trigonometric ratios for ∆ABD can be done as follows:
Let BD = x
AB = c
AD = b
=>The sine ratio for the length of line segment BD = x, using SOH.
θ = A
Opposite = DB = x
hypotenuse = AB = c
Make x the subject of formula.
=>The Cosine ratio for the length of line segment BD = x, using CAH
θ = B
Adjacent = DB = x
hypotenuse = AB = c
Make x the subject of formula.
=>The Tangent ratio for the length of line segment BD = x, using TOA
θ = A
Adjacent = DB = x
hypotenuse = AD = b
Make x the subject of formula.
Answer:
Step-by-step explanation:
This is calculus, but I don't get fractions in the end. To maximize or minimize any function, you need to find the derivative of it, set it equal to 0, then solve for the critical values.
Our given equation is
x + y = 215 and we want to maximize the product, xy. Therefore,
y = 215 - x so its product in terms of x is
x(215-x) which is
. The derivative of this is
215 - 2x. Set it equal to 0 to maximize it.
215 - 2x = 0 so
-2x = -215 and
x = 107.5.
Sub this in to solve for y:
y + 107.5 = 215 and
y = 107.5
The product is 11556.25, not that you need it.