The table shows the ages of Lily and Joe.

A cube has a volume of 125 cube inches. what is the length of each edge

yanalaym [24]

Answer:

5 cubic in. would be the length of each edge.

Step-by-step explanation:

volume = length * width * heigh

125 = 5 * 5 * 5

3 0

3 years ago

A rock outcrop was found to have 95.82% of its parent U- 238 isotope remaining. Approximate the age of the outcrop. The half-lif

mixer [17]

Answer:

A) 277 million years

Step-by-step explanation:

Here, decay of U-238 is first order reaction. (since most of the nuclear decays are first order).

so, the equation t = $\frac{1}{k}$ × ln( $\frac{A(0)}{A}$ )

where, t = time from start of reaction

k = reaction constant

A(0) = initial concentration; A = present concentration.

⇒ 4.5 billion = 4500 million years = $\frac{1}{k}$ × ln2.

Now, given 95.82% of parent U-238 isotope is left.

⇒ t = $\frac{1}{k}$ × ln( $\frac{A(0)}{A}$ )

t = $\frac{4500}{ln2}$ × ln( $\frac{100}{95.82}$ )

⇒ t ≅ 277 million years.

5 0

3 years ago

In order to solve the system of linear equations, the coefficients of one of the variables must be the same number but opposite

Mashutka [201]

Answer:

Step-by-step explanation:

because both equations do not have matching numbers for the x or y variable, and both equations are positive you are going to have to multiply each equation by a number so that there will be at least one variable with the same number but with opposite signs.

it does not matter which variable you choose.

lets use y because 2 and 3 are smaller then 2 and 5.

so lets multiply the first equation by 2 in order to get y equal to 6.

2(2x)+2(3y)=(2)6

(do not forget to multiply what the equation is equal to also)

4x+6y=12

now for the second equation we need y to equal negative 6

-3(5x)+-3(2y)=-3(4)

-15x-6y=-12

now lets put the 2 new equations next to each other and see what we can cancel out

4x+6y=12

-15x-6y=-12

-11x=0

x=0

now plug 0 in for x and solve for y (it does not matter which of the 4 equations you choose to solve.

2(0)+3y=6

3y=6

y=2

so your answer is x=0, y=2

8 0

3 years ago

I know that real numbers consist of the natural or counting numbers, whole numbers, integers, rational numbers and irrational nu

ra1l [238]

The imaginary unit $i$ belongs to the set of complex numbers, denoted by $\mathbb C$ . These numbers take the form $a+bi$ , where $a,b$ are any real numbers.

The set of real numbers, $\mathbb R$ , is a subset of $\mathbb C$ , where each number in $\mathbb R$ can be obtained by taking $b=0$ and letting $a$ be any real number.

But any number in $\mathbb C$ with non-zero imaginary part is not a real number. This includes $i$ .

"is it possible that i can use an imaginary number for a real number"

I'm not sure what you mean by this part of your question. It is possible to represent any real number as a complex number, but not a purely imaginary one. All real numbers are complex, but not all complex numbers are real. For example, 2 is real and complex because $2=2+0i$ .

There are some operations that you can carry out on purely imaginary numbers to get a purely real number. A famous example is raising $i$ to the $i$ -th power. Since $i=e^{i\pi/2}$ , we have

$i^i=\left(e^{i\pi/2}\right)^i=e^{i^2\pi/2}=e^{-\pi/2}\approx0.2079$

3 0

3 years ago

Please help <br> Solve: 2x2-x = 21

maksim [4K]

The answer is x= -17
hope this helps

5 0

3 years ago