Question

Add (2+3i) + (4-6i) I need help I have to show all work

Answer 1

ANSWER:

The answer on solving the given equation (2+3i) + (4-6i) is 6-3i.

SOLUTION:

We have been asked to add (2+3i) + (4-6i).  

‘i’ is a complex number or can be called an imaginary number, it can be said to have a value of $\sqrt{-1}$ which is non-existent. But $i^2$ has a value of -1.

So, in the given equation we just have to add the given terms.

Therefore, the answer becomes:

=2 + 3i + 4 - 6i

Add like terms we get,

=6 - 3i

The answer on solving the given equation is 6-3i.

Answer 2

Explanation: Just add like terms, picture is attactched