Add (2+3i) + (4-6i) I need help I have to show all work
2 answers:
<u>ANSWER: </u>
The answer on solving the given equation (2+3i) + (4-6i) is 6-3i.
<u>SOLUTION: </u>
We have been asked to add (2+3i) + (4-6i).
‘i’ is a complex number or can be called an imaginary number, it can be said to have a value of which is non-existent. But
has a value of -1.
So, in the given equation we just have to add the given terms.
Therefore, the answer becomes:
=2 + 3i + 4 - 6i
Add like terms we get,
=6 - 3i
The answer on solving the given equation is 6-3i.
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The interpretation is that;
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