There are multiple ways to do this.
The easiest is to just continuously subtract 7 from 65 the numbers of times needed.
But most math teachers will have you use the equation ar^n-1 where a= the first term (65), r=ratio (-7), and n=the term you need (second, fifth, and ninth).
So to solve you just plug your values in as so
AR^n-1
(65)(-7)^2-1(65)(-7)^5-1
(65)(-7)^9-1
Answer:
5
Step-by-step explanation:
There are 2 ways to look at this. I will explain both.
First we have the 3-4-5 triangle method, stating that any triangle with sides 3 and 4 will have the last side as 5.
Now, for the more complex way of doing this, we can use the Pythagorean theorem to solve this problem.
Pythagorean theorem: 
We can use 4 for a and 3 for b
You will now have
Then take √25, or 5.
Hey mate!
1st up, we must use the (Order of operations) If you don't know what that is, then it is better known as PEMDAS.
(143(5) + 67)(5)
143 x 5 =715
(715 + 67)(5)
782 x 5 = 3910
The end product is 3,910
Hope this helps!
Standard form means, move the variables to the left-hand-side and leave the constant all by herself on the right-hand-side, usually sorting the variables, so"x" goes first.
now, there's a denominator, we can do away with it, by simply multiplying both sides by the denominator, so let's do so,
(I) The 15 represents the money earned for each ticket sold
In other words the 15 is the cost of each ticket.
(II) The 700 represents the costs inquired when organizing the dance
In other words...how much it costs to throw the dance.
<u>Explanation</u>
Since t is the number of tickets and the function shows profit we know that every step on the left has some aspect to do with the profit....for ever ticket (t) sold there is an addition of 15 dollars...or for every 1 ticket sold $15 is earned....or each ticket costs 15 dollars
The -700 shows that 700 dollars must be subtracted from the total income from selling tickets....since this is looking for profit which is income-costs and we have already determined that 15t represents the income we know that the 700 must represent the costs of throwing the dance.
