Prove that there are no solutions in integers x and y to the equation 2x^2 + 5y^2 = 14
1 answer:
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Cosine and secant functions are reciprocal, which means
So, if
then
I hope this helps. =)
Tags: <em>cosine secant cos sec relation reciprocal trig trigonometry</em>
_______________
Cosine and secant functions are reciprocal, which means
So, if
I hope this helps. =)
Tags: <em>cosine secant cos sec relation reciprocal trig trigonometry</em>
<h2>Explanation:</h2><h2></h2>
Hello! Remember you have to write complete questions in order to get good and exact answers. Here you forgot to write the relation so I could help you providing my own relation.
Remember that for any relation, we have a set that matches the the domain (also called the set of inputs) of the function and the set
that contains the range (also called the set of outputs).
Suppose our relation is:
So the x-values represents the set A and the y-values the set B. Therefore, by evaluating the x-values into our relation we get:
So in this context, the correct option is:
B) (-9,-8, -7, -6, -5}