Question

Which equation describes a line perpendicular to line r that passes through the point (3,-6) x-3y=21, 3x+y=3, 3x-y=15, 3x-y=3

Answer 1

Answer:

See Explanation

Step-by-step explanation:

Missing in the question is the slope of line r.

We'll assume that the slope (m) of line r is

$m = -\frac{1}{3}$

When two lines are perpendicular, their slope are related in:

$m_2 = -1/m_1$

$m_2 = -1/\frac{-1}{3}$

$m_2 = -1 * -3$

$m_2 = 3$

The equation of the (3,-6) is:

$y - y_1 = m(x - x_1)$

Where

$(x_1,y_1) = (3,-6)$

So:

$y - (-6) = 3(x - 3)$

$y +6 = 3x - 9$

Make y the subject

$y = 3x - 9 - 6$

$y = 3x - 15$

Please note that this answer might be incorrect to you based on the assumed value. However, the step will guide you in solving similar questions