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lisabon 2012 [21]
3 years ago
6

Will mixing 4 parts red with 3 parts yellow make the same shade of orange as 12 parts red and 6 parts yellow

Mathematics
2 answers:
Over [174]3 years ago
8 0
Nope it will make it more of a red orange
jolli1 [7]3 years ago
5 0

Answer:

No

Step-by-step explanation:

No because the ratio is 4:3

Doing 12 parts and 6 parts would make the ratio 6:3 and would also make a much more red orange.

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Which of these tables represents a non-linear function?
olchik [2.2K]

Answer:

we conclude that the table ''A 2-column table with 4 rows. Column 1 is labeled x with entries 17, 18, 19, 20. Column 2 is labeled y with entries 16, 17, 19, 20'' represents a non-linear function.

Step-by-step explanation:

The nature of whether a function can be linear or non-linear, we must check how the x and y values of the table change. If the first difference between y-values remains the same (constant first difference), then the table will represent a linear function, otherwise not.

Given the x and y entries of the first table:

x            y

17           20

18           19

19           18

20          17

From the table, it is clear that as x constantly increases by 1 unit, the y-values are also changing constantly by 1 unit. The first difference between y-values remains the same.

i.e. 19-20=-1, 18-19=-1, 17-18=-1

Thus, this table represents a linear function.

Given the x and y entries of the second table:

x            y

17          -16

18          -17

19           -18

20          -19

From the table, it is clear that as x constantly increases by 1 unit, the y-values are also changing constantly by 1 unit. The first difference between y-values remains the same.

i.e. -17-(-16)=-1, -18-(-17)=-1, -19-(-18)=-1

Thus, this table represents a linear function.

Given the x and y entries of the second table:

x            y

17          16

18          17

19           19

20          20

From the table, it is clear that as x constantly increases by 1 unit, but the y-values are not changing constantly. The first difference between y-values does not remain the same.

i.e. 17- 16 = 1, 19 - 17 = 2, 20 - 19 = 1

Thus, this table does not represent a linear function. Hence, it is a non-linear function.

Given the x and y entries of the second table:

x            y

17          -20

18          -19

19           -18

20          -17

From the table, it is clear that as x constantly increases by 1 unit, the y-values are also changing constantly by 1 unit. The first difference between y-values remains the same.

i.e. -19-(-20)=1, -18-(-19)=1, -17-(-18)=1

Thus, this table represents a linear function.

Therefore, we conclude that the table ''A 2-column table with 4 rows. Column 1 is labeled x with entries 17, 18, 19, 20. Column 2 is labeled y with entries 16, 17, 19, 20'' represents a non-linear function.

4 0
3 years ago
Jamie Nolan purchased new cabinets for $12,640: laminate flooring for $4,560; countertops for
Goryan [66]

Answer:

total : 12371747

down payment : 10,515,984.95

Step-by-step explanation:

3 0
2 years ago
A number cube is rolled. What is the probability that the cube lands on an odd number.
padilas [110]

Answer:

1/3 or 3/6 they are the same thing

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Please help asap<br> What is the least common denominator of the fractions?
Reil [10]
The answer is B. 6m^3n^5. Hope I actually helped!
6 0
3 years ago
What is the domain of the square root function graphed below?
erma4kov [3.2K]

Answer:

The domain of the graph must be x\ge \:-4.

Therefore,

x\ge \:-4\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x\ge \:-4\:\\ \:\mathrm{Interval\:Notation:}&\:[-4,\:\infty \:)\end{bmatrix}

Hence, option a is true.

Step-by-step explanation:

From the graph, it is clear that the graph is heading towards positive infinity from x=-4.

The point x=-4 is included in the graph as the starting point of the graph i.e. x=4 is showing a closed circle on x=4, and heading towards positive infinity onward.

i.e. [-4, ∞)

Hence, the domain of the graph must be x\ge \:-4.

Therefore,

x\ge \:-4\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x\ge \:-4\:\\ \:\mathrm{Interval\:Notation:}&\:[-4,\:\infty \:)\end{bmatrix}

Hence, option a is true.

3 0
3 years ago
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