Question

Write an equation of the line that goes through the point (–6, 6) and is perpendicular to the line y=-2x+2

Answer 1

Answer:

Slope-intercept form: y = x/2 + 9

Standard form: x - 2y = -18

Step-by-step explanation:

y = -2x + 2

This equation is already in slope-intercept form, y= mx + b, where slope (m) is equal to -2.

Slope of the line perpendicular to the given line

= 1/2 passing through point (-6, 6)

y - 6 = (1/2)(x + 6)

y = (1/2)x + 9 (Slope-intercept form)

2y = x + 18

x - 2y = -18 (Standard form)