Answer:
16.32 N11.38°E km/h
Step-by-step explanation:
16.0∠0° +3.22∠90° ⇒ (x, y) = (3.22, 16.0) ⇒ (r, θ) =
(3.22, 16.0) ⇒ (r, θ) = (√(3.22² +16²), arctan(3.22/16)*) = (16.32, 11.38°)
The woman's velocity is 16.32 km/h in a direction that is 11.38° east of north.
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This is her velocity in any stationary frame of reference.
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* We have used North as the reference for the angle, measured CW.
