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3 years ago

8

A company is running a contest and offering a first, second, and third prize. First prize is a choice

2 answers:

dedylja [7]3 years ago

7 0

If cash prizes are to be avoided, then . . .

-- The first prize has to be a car.

-- The second prize can be a motorbike or a trip ... 2 possibilities.
For each of those . . .

-- The third prize has to be a TV.

Since there's no choice with the first or third prizes,
I only see two different ways to avoid a cash prize.

creativ13 [48]3 years ago

4 0

The answer is to be a car

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What is 7x + 6 +2x = 60 .

Aloiza [94]

Answer:

$x = 6$

Step-by-step explanation:

$7x + 6 + 2x = 60 \\9x + 6 = 60$

add $-6$ to both sides

$9x + 6 - 6 = 60 - 6 \\9x = 54$

Divide both sides by $9$

$\frac{9x}{9} = \frac{54}{9}$

$x = 6$

6 0

4 years ago

Bradley and Louie are roommates at college. At the beginning of the semester, they each paid a security deposit of A

Pie

An expression that describes how much each person will receive from the landlord when the lease expires is; A - (B/2) = R. And the amount received by each person as described is; $100

Since, Bradley and Louie are expected to each pay a security deposit of A;

In essence, amount paid by each person is; A

Since, the total expenses = B and is to be shared by Bradley and Louie equally; we have;

Each person pays expenses charge; B/2.

An expression that describes how much each person will receive from the landlord when the lease expires is;

<em>A - (B/2) = R</em>.

Ultimately, when each person pays, A = $125 and damages charge = $50;

The amount received by each person is;

R = 125 - (50/2)

R = $100

Read more on lease charge;

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7 0

3 years ago

QS−→ bisects m∠PQR and m∠PQR = 124∘.<br><br><br><br> Find m∠PQS and m∠RQS.

Ainat [17]

PQS is congruent to RQS
124/2 = 62°

7 0

3 years ago

If dy/dx=4y and y=4 when x=0, then y=. A) 4e^4x. B) e^4x. C) 3+e^4x. D) 4+e^4x. e) 2x^2+4

aliina [53]

Hello,

dy/dx=4==>dy/y=4dx==>ln(y)=4x+C
==>y=k*e^(4x)
if x=0 y=4==>4=k*e^(4*0)==>k=4

==>y=4*e^(4x)

Answer A (with parenthesis!!!)

8 0

3 years ago

Which logarithmic equation is equivalent to the exponential equation below?

aleksandr82 [10.1K]

Option B: $\ln 6=5 x$ is the correct answer.

Explanation:

The exponential equation is $e^{5 x}=6$

If $f(x)=g(x)$ , then $\ln (f(x))=\ln (g(x))$

Thus, the equation becomes

$\ln \left(e^{5 x}\right)=\ln (6)$

Applying log rule, $\log _{a}\left(x^{b}\right)=b \cdot \log _{a}(x)$ and thus the equation becomes

$5 x \ln (e)=\ln (6)$

Since, we know that, $\ln (e)=1$ , using this we get,

$5 x=\ln (6)$

Hence, the logarithmic equation which is equivalent to the exponential equation $e^{5 x}=6$ is $\ln 6=5 x$

Thus, Option B is the correct answer.

7 0

3 years ago