Smh kid we dont just answer the question u supposed to know the math
Answer:
is it 3?<em><u> </u></em>(jk)<em><u>it is42</u></em>
Step-by-step explanation:
<span>Give that </span>t<span>he frequency of G5 is 783.99 Hz.
To find the frequency of the note that is a perfect fifth above G5, we recall that </span>the frequencies of notes that are a 'perfect'
fifth apart are in the ratio of 1.5
i.e. <span>the frequency of the note that is a perfect fifth above G5 divided by </span><span>t<span>he frequency of G5 equal 1.5
Let the </span></span><span><span>frequency of the note that is a perfect fifth above G5 be F, then
F / </span>783.99 = 1.5
F = 1.5 x 783.99 = 1175.99
Therefore, </span>the <span>frequency of the note that is a perfect fifth above G5</span> is 1175.99 Hz
Answer:
a. 3 and 56, respectively.
Step-by-step explanation:
The computation of the degrees of freedom for the numerator and denominator for the critical value of F is given below:
k = 4
n = 15
Total degree of freedom is
= nk - 1
= 59
For numerator, it is
= k -1
= 4 - 1
= 3
and for denominator it is
= T - (k -1 )
= 59 - 3
= 56
