Which are real zeros of this function x^3+2x^2-9x-18
1 answer:
To solve the problem shown above, you must follow the proccedure shown below:
1. You the following polynomial of degree 3:
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x^3+2x^2-9x-18
2. When you factor it, you obtain:
(x+2)(x-3)(x+3)=0
3. Then, you obtain:
x1=-2
x2=3
x3=-3
4. Therefore, the correct answer is the last option (option e), which is shown below:
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e) -2,3,-3</span>
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21) option C
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Hope this help :-) in the picture u going to see the steps. The answer is 13
Answer:
d=~7.6
Step-by-step explanation:
7^2+3^2=d^2
49+9=d^2
58=d^2
Square root of 58=~7.6
d=~7.6
Answer:
145
Step-by-step explanation:
75% of 200 = 150
75% + 15% = 90%
100% - 90% = 10%
10% of 200 = 20
10% of 150 = 15
150 + 15 - 20 = 145
145 friends attended the party.