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ivanzaharov [21]
3 years ago
10

I NEED HELP! NO LINKS JUST ANSWERS!

Mathematics
1 answer:
Ket [755]3 years ago
6 0

Answer:

7065 cm^3

Step-by-step explanation:

tell me if you got it wrong

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A rectangle has vertices H(3,0), I(3,7), J(6,7) , and K(6, 0) . Use the coordinates to find the perimeter of the rectangle. _uni
Paul [167]

Answer:

20 units

Step-by-step explanation:

Plot points on a graph. doesn't have to be to scale. check co-ordinates differences and add up. see image.

4 0
2 years ago
Please help I don’t understand this.
tresset_1 [31]

The average rate of change of <em>g(x)</em> over the interval [2, 8] is given by

(<em>g</em> (8) - <em>g</em> (2)) / (8 - 2)

In other words, it's the slope of the line through the points (2, <em>g</em> (2)) and (8, <em>g</em> (8)).

Use the definition of the function to evaluate it at the points in the numerator:

• 8 ≥ 4, so using the second piece, <em>g</em> (8) = -0.5(8) + 8 = 4

• 2 < 4, so <em>g</em> (2) = 5(2) + 1 = 11

Then the average rate of change is

(<em>g</em> (8) - <em>g</em> (2)) / (8 - 2) = (4 - 11) / 6 = -7/6

3 0
3 years ago
A lacrosse player throws a ball into the air from a height of 6 feet with an initial vertical velocity of 64 feet per second. Wh
-Dominant- [34]

Answer:

Step-by-step explanation:

I'm going to use calculus to solve this, because it's the simplest way.  

The acceleration due to gravity in feet is the second derivative of the position function.  We will start with the acceleration and work backwards with antiderivatives to get to the position function.

a(t) = -32.  Going backwards and using the fact that the initial vertical velocity is 64 ft/sec, our velocity function is

v(t) = -32t + 64.  Going backwards and using the fact that the initial height of the ball is 6 feet, our position function is

s(t)=-16t^2+64t+6

The first part of this question asks us the maximum height of the ball.  From Physics, we learn that the maximum height of a projectile is reached when the velocity is 0, which happens to be right where the projectile stops for a nanosecond in the air to turn around and come back down.  We set the velocity function equal to 0 and solve for t.

0 = -32t + 64 and

0 = -32(t - 2).  By the Zero Product Property, either -32 = 0 or t - 2 = 0.  It's obvious that -32 does not equal 0, so t - 2 must equal 0.  Solving this for t:

t - 2 = 0 so

t = 2 seconds.  Since the maximum height is reached at a time of 2 seconds, we plug 2 seconds into the position function to get its position at 2 seconds (which is also the max height of the ball).

s(2)=-16(2)^2+64(2)+6 and

s(2) = -64 + 128 + 6 so

s(2) = 70 feet

Now we want to know when the ball will hit the ground.  "When" is a time value, and we know that the height of the ball on the ground is 0, so we sub in a 0 for s(t) and factor the quadratic.

Using the quadratic formula:

t=\frac{-64+/-\sqrt{4096-4(-16)(6)} }{-32} and

t=\frac{-64+/-\sqrt{4480} }{-32} which gives us the 2 solutions

t=\frac{-64+\sqrt{4480} }{-32} and

t=\frac{-64-\sqrt{4480} }{-32}

Plugging into your calculator, the first t = -.0916500 and the second t = 4.091

We all know that time cannot ever be negative, so our t value is 4.09.

Again, from Physics, we know that a projectile reaches it max height at halfway through its travels, so it just goes to follow logically that if it halfway through its travels at 2 seconds, then it will hit the ground at 4 seconds.  And it does!! How awesome is that?!

4 0
3 years ago
A car rental company charges $31 per day to rent a particular type of car, and $0.19 per mile. Juan is charged $59.31 for a one-
snow_lady [41]

x = # of miles

$59.31 = $31 + $0.19x

Subtract $31 from both sides

$28.31 = $0.19x

Divide both sides by $0.19

149 = x

Juan drove 149 miles

5 0
3 years ago
I need help its the triangle sum theorem​
Dimas [21]
I think it might be C
4 0
3 years ago
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