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wlad13 [49]
3 years ago
7

3х + 5у = -3x+2y = - 4/3​

Mathematics
1 answer:
Katena32 [7]3 years ago
5 0
I’m solving for x
X =2/3
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If A = 10 feet, B = 6 feet, C = 1 foot, D = 14 feet, and E = 2 feet, what is the area of the object?
Bogdan [553]

Answer:


Step-by-step explanation:


3 0
3 years ago
Can someone pls help me with this !
Vadim26 [7]

Using a line of best fit, the predicted tsunami speed for the following depths is given by:

a. 1151 km/h.

b. 572 km/h.

c. 130 km/h.

d. 122 km/h.

<h3>How to find the equation of linear regression using a calculator?</h3>

To find the equation, we need to insert the points (x,y) in the calculator.

For this problem, the points (depth, velocity) are given by:

(7000, 943), (4000, 713), (2000, 504), (200, 159), (50, 79), (10,36)

Inserting these points in the calculator, the velocity in function of the depth is:

v(d) = 0.12879d + 121.03448

Hence, the velocities are given as follows:

a. v(8000) = 0.12879 x 8000 + 121.03448 = 1151 km/h.

b. v(3500) = 0.12879 x 3500 + 121.03448 = 572 km/h.

c. v(70) = 0.12879 x 70 + 121.03448 = 130 km/h.

d. v(5) = 0.12879 x 5 + 121.03448 = 122 km/h.

More can be learned about a line of best fit at brainly.com/question/13203683

#SPJ1

8 0
1 year ago
Find the integral using substitution or a formula.
Nadusha1986 [10]
\rm \int \dfrac{x^2+7}{x^2+2x+5}~dx

Derivative of the denominator:
\rm (x^2+2x+5)'=2x+2

Hmm our numerator is 2x+7. Ok this let's us know that a simple u-substitution is NOT going to work. But let's apply some clever Algebra to the numerator splitting it up into two separate fractions. Split the +7 into +2 and +5.

\rm \int \dfrac{x^2+2+5}{x^2+2x+5}~dx

and then split the fraction,

\rm \int \dfrac{x^2+2}{x^2+2x+5}~dx+\int\dfrac{5}{x^2+2x+5}~dx

Based on our previous test, we know that a simple substitution will work for the first integral: \rm \quad u=x^2+2x+5\qquad\to\qquad du=2x+2~dx

So the first integral changes,

\rm \int \dfrac{1}{u}~du+\int\dfrac{5}{x^2+2x+5}~dx

integrating to a log,

\rm ln|x^2+2x+5|+\int\dfrac{5}{x^2+2x+5}~dx

Other one is a little tricky. We'll need to complete the square on the denominator. After that it will look very similar to our arctangent integral so perhaps we can just match it up to the identity.

\rm x^2+2x+5=(x^2+2x+1)+4=(x+1)^2+2^2

So we have this going on,

\rm ln|x^2+2x+5|+\int\dfrac{5}{(x+1)^2+2^2}~dx

Let's factor the 5 out of the intergral,
and the 4 from the denominator,

\rm ln|x^2+2x+5|+\frac54\int\dfrac{1}{\frac{(x+1)^2}{2^2}+1}~dx

Bringing all that stuff together as a single square,

\rm ln|x^2+2x+5|+\frac54\int\dfrac{1}{\left(\dfrac{x+1}{2}\right)^2+1}~dx

Making the substitution: \rm \quad u=\dfrac{x+1}{2}\qquad\to\qquad 2du=dx

giving us,

\rm ln|x^2+2x+5|+\frac54\int\dfrac{1}{\left(u\right)^2+1}~2du

simplying a lil bit,

\rm ln|x^2+2x+5|+\frac52\int\dfrac{1}{u^2+1}~du

and hopefully from this point you recognize your arctangent integral,

\rm ln|x^2+2x+5|+\frac52arctan(u)

undo your substitution as a final step,
and include a constant of integration,

\rm ln|x^2+2x+5|+\frac52arctan\left(\frac{x+1}{2}\right)+c

Hope that helps!
Lemme know if any steps were too confusing.

8 0
3 years ago
9 millimeters to centimeters
Oxana [17]
9 millimeters= 0.9 centimeters
6 0
3 years ago
If M and m represents the number of sexagesimal and centesimal minute of any angle respectively, prove that M/27=m/50.​
riadik2000 [5.3K]

Answer:

if ma and m id black life matters if balck

7 0
3 years ago
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