3 years ago

Which is the best estimate of square root 47 to the nearest tenth?

2 answers:

6 0

You were close in the picture. 6.9

And because I prefer to be accurate, ten decimal places would be <span>6.8556546004</span>

-Dominant- [34]3 years ago

4 0

The answer is B. 6.9

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Determine the angle at the centre of a circle with radius 6.0 cm for an arc length of 8.0 cm.

sveta [45]

Answer:

Third option.

Step-by-step explanation:

You need to remember that the formula used to calculate the arc lenght is:

$arc\ length=r C$

Where "r" is the radius and "C" is the central angle in radians.

You need to solve for "C":

$C=\frac{arc\ length}{r}$

You know the radius and the arc lenght, therefore, you can substitute values to calculate the central angle in radians. Therefore, this is:

$C=\frac{8.0cm}{6.0cm}$

$C=\frac{4}{3}radians$

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3 years ago

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lisabon 2012 [21]

Answer:

Step-by-step explanation:

(x – 4)(x – 4) = 0.

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3 years ago

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Sphinxa [80]

the answer would be -b

5 0

4 years ago

Consider vectors u and v, where u = (1, -1) and v = (1, 1). What is the measure of the angle between the vectors?

7nadin3 [17]

Answer:

I believe the answer is C. 90 degrees

Step-by-step explanation:

First you find the lengths of the two vectors, which are both $\sqrt{2}$ . Then you find the angle given the cos using: cos(∅)= $\frac{u*v}{|u|*|v|}$ = $\frac{0}{\sqrt{2}*\sqrt{2} }$ = 0. Then using ∅=acos(0)= $\frac{\pi }{2}$ = 90°

6 0

3 years ago

Read 2 more answers

Please please help me with this

iris [78.8K]

Answer:

angle FQE= Minor sector

6 0

3 years ago