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scoundrel [369]
2 years ago
6

Find the rate of change of the linear function shown in the graph. Then find the initial value.

Mathematics
1 answer:
pantera1 [17]2 years ago
6 0

Answer

ok

Step-by-step explanation

ok

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a_sh-v [17]
2 hours she earns €16
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3 years ago
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A population, P(t) (in millions) in year t, increases exponentially. Suppose P(9)=16 and P(18)=24. a) Find a formula for the pop
jenyasd209 [6]

Answer:\frac{32}{3}\left ( 1.0460\right )^t

Step-by-step explanation:

Given

Population changes exponentially

P\left ( t\right )=ab^t

P\left ( 9\right )=16------1

P\left ( 9\right )=16=ab^8

P\left ( 18\right =24=ab^{18}-----2

divide 1 & 2 we get

\frac{24}{16}=\frac{b^{18}}{b^9}

\frac{3}{2}=b^9

Substitute b^9 in 1 we get

a=\frac{32}{3}

Thus P\left ( t\right )=\frac{32}{3}\left ( 1.0460\right )^t

8 0
3 years ago
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4 1/6 + 5 2/3Enter your answer as a mixed number in simplest form
galina1969 [7]

Answer:

Step-by-step explanation:

First, change the mixed numbers into improper fractions:

5 2/3 = 17/3

Then, find the common denominator:

41/6 + 17/3=

LCM = 6

17/3 *2 = 34/6

41/6 + 34/6

Last, Add

25/6  or

12 1/2

Hope this helps!

mark brainliest if possible!

3 0
2 years ago
Verify identities Will give BRAINLIST<br><br> cot^2(x) - csc^2(x) = -1<br><br> show steps
san4es73 [151]

Answer:

Step-by-step explanation:

∫tan(x)dx∫cot(x)dx∫sec(x)dx∫csc(x)dx====−ln∣∣cos(x)∣∣+C=ln∣∣sec(x)∣∣+Cln∣∣sin(x)∣∣+C=−ln∣∣csc(x)∣∣+Cln∣∣sec(x)+tan(x)∣∣+C−ln∣∣csc(x)+cot(x)∣∣+C

4 0
3 years ago
What is the range of the function graphed below?
PilotLPTM [1.2K]

Answer:

[-4,0) ∪ [2, ∞)

Step-by-step explanation:

For piecewise function domain and range, we need to understand the difference between "(" and "["  or  ")" and "]"

  • The parenthesis ( "(" and ")" ) are used for "open circles" in the graph.
  • The brackets ( "[" and "]" ) are use for "closed circles" in the graph.

Range is the set of y-values for which the function is defined.

Now,

The upper part of the function shows the graph going from y = 2 towards infinity (arrow). At y = 2 , there is closed circle, so this part range would be

[2, ∞)  (infinity is always with parenthesis)

Now, looking at bottom part, the function is defined from 0 (open circle) to -4 (closed). so we can write:

[-4,0)

This is the range, 2nd answer choice is correct.

[-4,0) ∪ [2, ∞)

3 0
3 years ago
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