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2 years ago

I dont know what I'm doing

Mathematics

1 answer:

irakobra [83]2 years ago

3 0

To find the equations what you have to do is use the given points and the slope.

If the line is parallel then the slope will be the same and if it is perp. then the slope will be opposite an reciprocal.

So, you use the point slope form, y-y1 = m(x-x1), and then simplify it to get to the slope intercept form.

y1 is the y coordinate of the given point, m is the slope and x1 is the x coordinate of the given point.

22) The line is parallel so the slope are going to be the same.

y - 5 = 4 (x - 2)
y - 5 = 4x - 8
y = 4x - 3

So the equation parallel to that line would be y = 4x - 3

26) The line is perp. so the slope will be opposite and reciprocal.

y - (3) = -1/2 (x - (-4))
y + 3 = -1/2 (x + 4)
y + 3 = -1/2x - 2
y = -1/2 x - 5

So the equation to the perp. line will be y = -1/2x - 5

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Tammys desk had 7/12 grams of dust on it she wiped away 5/12 grams of the dust how many grams of dust are left on her desk write

nexus9112 [7]

Answer:

2/12

Step-by-step explanation:

7/12 -5/12 = 2/12

the number 2 can go into 2 once and 12 six times so you should get 1/6 as your answer

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2 years ago

What is the area of a rhombus with dimensions of 22 inches and 10 inches?

docker41 [41]

The answer to the problem is 220

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3 years ago

Read 2 more answers

Solve for y: 2y + 3 =11<br><br>Solve for x:<br>2/3x = 18

laiz [17]

Answer: y=4 x=27

Step-by-step explanation: 2y+3=11

-3 -3

2y=8

/2 /2

y=4

2/3x=18

(3) (3)

2x=54

/2 /2

X=27

5 0

3 years ago

Read 2 more answers

If sally got 28 questions correct and received 70% on the exam, how many questions were on the exam

Furkat [3]

Answer: 40

Step-by-step explanation:

Number of correct questions Sally got = 28 questions

Percentage of correct questions answered= 70% on the exam,

Total number of questions in the exam = Unknown

Let the total questions in the exam be represented as y.

Since Sally got 70% correctly, this will be:

70% of y = 28

70/100 × y = 28

0.7 × y = 28

0.7y = 28

Divide both side by 0.7

0.7y/0.7 = 28/0.7

y = 40

There are 40 questions in the exam.

7 0

3 years ago

On a town map, each unit of the coordinate plane represents 1 mile. Three branches of a bank are located at A(−3, 1), B(3, 3), a

Andrei [34K]

Answer:

The minimum total distance the employee may have driven before getting stuck in traffic is 8.3 miles

Step-by-step explanation:

* Lets explain how to solve the problem

- The rule of the distance between to points $(x_{1},y_{1})$

and $(x_{2},y_{2})$ i s $d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$

- So at first we will find the distance between the three points

∵ A = (-3 , 1) , B = (3 , 3) , C = (3 , -1)

- By using the rule of distance

∴ $AB=\sqrt{(3--3)^{2}+(3-1)^{2}}=\sqrt{36+4}=\sqrt{40}=6.325$

∴ $BC=\sqrt{(3-3)^{2}+(-1-3)^{2}}=\sqrt{0+16}=4$

∴ $AC=\sqrt{(3--3)^{2}+(-1-1)^{2}}=\sqrt{36+4}=\sqrt{40}=6.325$

∵ Each unit coordinate plane represents 1 mile

∵ AB = 6.3 units

∴ The distance between branches A and B = 6.325 miles

∵ BC = 4 units

∴ The distance between branches B and C = 4 miles

∵ AC = 6.3 units

∴ The distance between branches A and C = 6.325 miles

- A bank employee drives from Branch A to Branch B and then

drives halfway to Branch C before getting stuck in traffic

∵ The distance from branch A to branch B is 6.325 miles

∵ The distance from branch B to branch C is 4 miles

∵ The half way from branch B to branch C = 1/2 × 4 = 2 miles

∴ The distance the employee may have driven before getting

stuck in traffic = 6.325 + 2 = 8.325 miles

∴ The minimum total distance the employee may have driven

before getting stuck in traffic is 8.3 miles

8 0

2 years ago