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murzikaleks [220]
3 years ago
11

PLEASE PLEASE HELP. What is the length of BC in the right triangle below?

Mathematics
1 answer:
frosja888 [35]3 years ago
8 0

Answer:

bc=39

Step-by-step explanation:

15^2+36^2=1521

the square root of 1521=39

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What is the volume of a square prism with a base area of 25 square centimeters and a height of 6 centimeters?
bonufazy [111]

Answer:

since, v=a(square) ×h

Step-by-step explanation:

v=a(squate)cm×hcm

v=25(square)cm×6cm

v=625cm×6ccm

v=3,750cm(cube)

7 0
3 years ago
The area of a square mural pointed on the side of a building is 110 square feet. What is the best estimate of the side length of
natka813 [3]

Answer:

C

Step-by-step explanation:

Area of a square equals to the square of its side, therefor the side of a given area for a square is the square root of the area.

A = a^{2}\\a = \sqrt{A}\\a = \sqrt{110} = 10.48 ft

8 0
3 years ago
7*z^(1/2)-3=2*z??? solve??/
Hoochie [10]

Answer:

Z €{9, i can right a fraction but on top is 9 below is 4}

Step-by-step explanation:

3 0
3 years ago
Solve the equation for y. Then find the value of Y for each value of X.
Hunter-Best [27]

Answer:

y=9-7x

If x= -1, y=16

If x= 0, y=9

If x=2, y= -5

Step-by-step explanation:

Because you are solving the equation for y, you want to have y by itself on one side. The only way to do that in this problem is by subtracting the 7x on both sides.

y+7x=9

-7x -7x ---> y=9-7x

The next part of the question says to find the value of Y for each value of X. Using the given X values, we plug them into the equation we just got in order to find Y.

y=9-7(-1) ----> y=16

y=9-7(0) ----> y=9

y=9-7(2) ----> y=-5

4 0
3 years ago
Read 2 more answers
PLZ HELP WILL GIVE BRAINLIEST WORTH 10 PTS THX!!
antiseptic1488 [7]

Answer:

  64/49

Step-by-step explanation:

The applicable rules of exponents are ...

  (a^b)^c = a^(bc)

  (a^b)(a^c) = a^(b+c)

  a^-b = 1/a^b

  a^0 = 1

_____

Using these rules, we can simplify the given expression to ...

  \left(\dfrac{8\cdot 4\cdot 2}{8\cdot 7}\right)^2\times\left(\dfrac{8^0}{7^{-3}}\right)^3\times 7^{-9}\\\\=\dfrac{8^2}{7^2}\times(8^{0\cdot 3}\cdot 7^{3\cdot 3})\times 7^{-9}\\\\=\dfrac{64}{49}\times(8^07^{9-9})=\boxed{\dfrac{64}{49}}

6 0
3 years ago
Read 2 more answers
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