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NISA [10]
2 years ago
15

Please help with these 3 pretty easy problems and explain how you got it!!! 100 POINTS AND BRAINLIEST!!!! Serious answers please

..

Mathematics
2 answers:
poizon [28]2 years ago
8 0

here are the answers!

1)

(x-3)/18=12/9, cross multiply

9(x-3)=18(12)

9x-27=216, add 27 to each side

9x=243, divide each side by 9

x=27

2)

(x-16)/(x+6)=3/5, cross multiply

5(x-16)=3(x+6)

5x-80=3x+18, subtract 3x from each side

2x-80=18, add 80 to each side

2x=98, divide each side by 2

x=49

3)

Since the triangles are similar we can say that

25/(4x-1)=10/(x+5), cross multiply

25(x+5)=10(4x-1)

25x+125=40x-10, subtract 40x from each side

-15x+125=-10, subtract 125 from each side

-15x=-135, divide each side by -15

x=9

natita [175]2 years ago
7 0

Answer:

Step-by-step explanation:

1)

(x-3)/18=12/9, cross multiply

9(x-3)=18(12)

9x-27=216, add 27 to each side

9x=243, divide each side by 9

x=27

2)

(x-16)/(x+6)=3/5, cross multiply

5(x-16)=3(x+6)

5x-80=3x+18, subtract 3x from each side

2x-80=18, add 80 to each side

2x=98, divide each side by 2

x=49

3)

Since the triangles are similar we can say that

25/(4x-1)=10/(x+5), cross multiply

25(x+5)=10(4x-1)

25x+125=40x-10, subtract 40x from each side

-15x+125=-10, subtract 125 from each side

-15x=-135, divide each side by -15

x=9

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19x+rx= -37x+w what is the x
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Answer:

x = w / (56 + r)

Step-by-step explanation:

Given the equation :

19x + rx= -37x + w ; find x

Collecting like terms

19x + rx + 37x = w

Factorizing x in the Left hand side

x(19 + 37 + r) = w

x(56 + r) = w

Therefore we can obtain x by dividing both sides by (56 + r)

x(56 + r) / (56 + r) = w / (56 + r)

x = w / (56 + r)

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Answer:Remember, the formula for slope is (y2 - y1) / (x2 - x1).

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The number of boots that 25 students had in their homes in Florida were recorded
wolverine [178]

Answer:

Min = 0; Q₁ = 0; Median = 2; Q₃ = 2; Max = 8

Step-by-step explanation:

Assume that your sorted data are

0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 3, 4, 5, 8

1. Minimum

Min = 0

2. Median

The median is the middle value in a sorted data set. There are 25 items, so the median is the 13th item.

Median = 2

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Q₁ is the median of the lower half of the data set.

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Q₁ = 0

4. Third quartile

Q₃ is the median of the upper half of the data set.

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table b'

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3 years ago
Would appreciate the help ! ​
aleksandr82 [10.1K]

This is one pathway to prove the identity.

Part 1

\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{1}{\tan(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\cot(\theta) = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{\cos(\theta)}{\sin(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)*\sin(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)(1-\cos(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\

Part 2

\frac{\sin^2(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)-\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-(\cos(\theta)-\cos^2(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-\cos(\theta)+\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\

Part 3

\frac{\sin^2(\theta)+\cos^2(\theta)-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1}{\sin(\theta)} = \frac{1}{\sin(\theta)} \ \ {\checkmark}\\\\

As the steps above show, the goal is to get both sides be the same identical expression. You should only work with one side to transform it into the other. In this case, the left side transforms while the right side stays fixed the entire time. The general rule is that you should convert the more complicated expression into a simpler form.

We use other previously established or proven trig identities to work through the steps. For example, I used the pythagorean identity \sin^2(\theta)+\cos^2(\theta) = 1 in the second to last step. I broke the steps into three parts to hopefully make it more manageable.

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