Question

Base your answer to the question on the diagrams shown below.

Answer 1

The probability of drawing a red card and spinning a 1 are independent events, thus to get the probability of them occurring at the same time we shall have:
P(Red)×P(Spinning 1)
P(Red)=2/5
P(Spinning 1)=4/8=1/2
Thus:
P(Red)×P(Spinning 1)=1/2×2/5=1/5

Answer 2

Answer: $\frac{1}{5}$

Step-by-step explanation:

From the given picture, the total number of cards = 5

The number of red card = 2

Thus, the probability of drawing a red card P(red)=$\frac{2}{5}$

Also, total number of digits on spinner = 8

Number of 1's=4

Thus, the probability of  spinning a 1 P( spinning 1)=$\frac{4}{8}=\frac{1}{2}$

Since both the events of drawing a red card and spinning a 1 are independent events, therefore, the probability of drawing a red card and then spinning a 1=$\text{ P(red)}\times\text{P( spinning 1)}=\frac{2}{5}\times\frac{1}{2}=\frac{1}{5}$