Ask question

Ask question

All categories

3 years ago

10

Which linear equations does the graph show the solution to? Select all that apply. y = 2x + 13 y = –x – 2 y = 3x – 5 y = negativ

e one-half x + 6 y = –2x – 2

2 answers:

polet [3.4K]3 years ago

8 0

Answer:

y = 2x + 13

y = –x – 2

Step-by-step explanation:

salantis [7]3 years ago

6 0

Answer:

y = 2x + 13

y = –x – 2

Step-by-step explanation:

The options are:

y = 2x + 13

y = -x - 2

y = 3x - 5

y= -(1/2)x + 6

y = -2x - 2

The graph is shown in the figure attached. There, point (-5, 3) is shown. Replacing it into the equations we get:

y = 2(-5) + 13 = 3 (so, it is a solution)

y = -(-5) - 2 = 3 (so, it is a solution)

y = 3(-5) - 5 = -20 ≠ 3 (so, it isn't a solution)

y= -(1/2)(-5) + 6 = 8.5 ≠ 3 (so, it isn't a solution)

y = -2(-5) - 2 = 8 ≠ 3 (so, it isn't a solution)

You might be interested in

HELP PLEASE ON 13- A, B, C<br><br>Can anyone tell me if the ones I did are right

KiRa [710]

13a.) If you're dividing and the base (in this case the base is 10) is the same, subtract the exponents.
${10}^{7} \div {10}^{5} = {10}^{7 - 5} = {10}^{2}$
13b.) If you're multiplying and the base is the same, then you add the exponents:

${s}^{2} \times {s}^{3} \times s = {s}^{2 + 3 + 1} = {s}^{6}$
13c.) This is similar to 13b:

${6}^{4} \times {6}^{3} \times 6 = {6}^{4 + 3 + 1} = {6}^{8}$

4 0

2 years ago

1. Ilove ordering cookies from Tiff's Treats (not

agasfer [191]

c = cost

h = # of half-dozens ordered

c = $8.50h + $1 is the correct answer.

4 0

2 years ago

A number cube is rolled 24 times and the results are recorded as follows: 2 ones, 4 twos, 7 threes, 4 fours, 3 fives, and 4 sixe

aksik [14]

I would say the answer would be 29.17% because $\frac{7}{24}$ =29.17%

Hope this helps

I'm so sorry if this is wrong

have a great day/night

4 0

2 years ago

PLEASE HELP ME!!!!!!!!!!!!!!!!!!

lilavasa [31]

Answer:

a) 4 - $vt - d = \frac{1}{2} at^{2}$

b) 1 - $2(vt - d) = at^{2}$

c) 6 - $\frac{2(vt - d)}{t^{2}} = a$

Step-by-step explanation:

It simply asks the steps to go from the original displacement formula to isolate a (the acceleration). It's just a matter of moving items around.

We start with:

$d = vt - \frac{1}{2} at^{2}$

We then move the vt part on the left side, then multiply each side by -1 (to get rid of the negative on the at side and to match answer choice #4):

$vt - d = \frac{1}{2} at^{2}$

Then we multiply each side by 2 to get rid of the 1/2, answer #1:

$2(vt - d) = at^{2}$

Finally, we divide each side by t^2 to isolate a (answer #6):

$\frac{2(vt - d)}{t^{2}} = a$

4 0

3 years ago

What is the difference in minutes of median

REY [17]

<h2>Answer:</h2>

The answer is 25 minutes

<h2>Step-by-step explanation:</h2>

As we see the median time given in minutes before the installation was 53 minutes and after the installation it became 28 so by taking the difference which is 53 - 28 gives us 25 minutes.

8 0

3 years ago