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patriot [66]
3 years ago
6

Rewards for answering the question below will be in place.

Mathematics
2 answers:
Darya [45]3 years ago
7 0

Answer:

It is the distance that - 5 is from 0 on the number line.

nadya68 [22]3 years ago
6 0

Answer:

It is the distance that - 5 is from 0 on the number line.

Step-by-step explanation:

We have to select a statement that is true about the value of StartAbsoluteValue negative 5 EndAbsoluteValue i.e. |- 5|

Definition of the absolute value function is given by, |x| = x for, x ≥ 0 and |x| = - x for x < 0.

Now, an absolute value function gives the positive value of any value in the function i.e. |- 5| = 5.

Therefore, it is the distance that - 5 is from 0 on the number line. (Answer)

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Henrietta solved a rational equation. Her work is shown. How could she solve it in a simpler way?
RoseWind [281]

Henrietta solved a rational equation by multiplying both sides by 3x^{2}(x+2) .She did not find the least common multiple of the denominators .If she had find the least common denominator which is 3x(x+2) then the question can have been simplified in more simpler form.

Henrietta can have got rid of denominator and then use the distributive rule .

So the first option

A:She could use the least common multiple of the denominator is right

4 0
3 years ago
Is 30:12 and 40:16 equivalent
iVinArrow [24]
Translate to fraction
are 30/12 and 40/16 equivilent?

if a/b=c/d then a/b times d/c=1
basically if ad=bc then they are equivilent

30/12 ad 40/16 equvilient?
30/12 times 16/40=1?
480/480=1?
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Which rule yields the dilation of the figure JKLM centered at the origin?
Sphinxa [80]
I’d say it’s between B and D
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Graph the ordered pairs for y = 4x + 2 <br> using {-2,1,2}
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No clue there has to be a graph paper for the answer
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Triangle Abc has vertices A(-2,5),B(1,0),andC(6,-2).what are the coordinates of the vertices of A’B’C for Ry-axis?
Andreyy89

Answer:

A'(2,5),B'(-1,0),C'(-6,-2)

Step-by-step explanation:

we know that

The rule of the reflection of a point across the y-axis is equal to

(x,y) -----> (-x,y)

so

Applying the rule of the reflection across the y-axis

A(-2,5) ----> A'(2,5)

B(1,0) -----> B'(-1,0)

C(6,-2) ---> C'(-6,-2)

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