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3 years ago

Using the given points and line, determine the slope of the line.

Mathematics

2 answers:

cupoosta [38]3 years ago

5 0

The answer will be B

Alona [7]3 years ago

3 0

slope = (y2-y1)/(x2-x1)

m= (1-2)/(2-1)

m=-1/1

m=-1

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Can someone help me please?

kodGreya [7K]

2/4 = 0.5
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3/8 = 0.375

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3 years ago

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clearance items in a store are all marked down proportionally. A shirt with an original price of $32 is on clearance of $12. wha

WINSTONCH [101]

Answer:

$15

Step-by-step explanation:

Set up a proportion where x is the clearance price of the $40 shirt:

$\frac{32}{12}$ = $\frac{40}{x}$

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32x = 480

x = 15

So, the clearance price is $15

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3 years ago

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The reference angle for 5pi/4 is 1, which has a terminal point of

maxonik [38]

Answer:

Step-by-step explanation:

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2 years ago

(8b^2/3*9t^3/5)(8b^5/3*9t^3/5)

erma4kov [3.2K]

Answer:

5,184•b•t^6/5

Step-by-step explanation:

Here, we want to multiply the expressions

According to indices law, if we have same bases, we add up the exponents

Thus, we have that;

8 *8b^(2/3+5/3) * 9 * 9 * t^(3/5+3/5)

= 64 * b * 81 * t^6/5

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8 0

2 years ago

A population has a standard deviation of 5.5. What is the standard error of the sampling distribution if the sample size is 81?

VladimirAG [237]

Answer:

$\sigma = 5.5$

And we have a sample size of n =81. We want to estimate the standard error of the sampling distribution $\bar X$ and for this case we know that the distribution is given by:

$\bar X \sim N(\mu ,\frac{\sigma}{\sqrt{n}})$

And the standard error would be:

$\sigma_{\bar x}= \frac{\sigma}{\sqrt{n}}$

And replacing we got:

$\sigma_{\bar x}=\frac{5.5}{\sqrt{81}}= 0.611$

Step-by-step explanation:

For this case we know the population deviation given by:

$\sigma = 5.5$

And we have a sample size of n =81. We want to estimate the standard error of the sampling distribution $\bar X$ and for this case we know that the distribution is given by:

$\bar X \sim N(\mu ,\frac{\sigma}{\sqrt{n}})$

And the standard error would be:

$\sigma_{\bar x}= \frac{\sigma}{\sqrt{n}}$

And replacing we got:

$\sigma_{\bar x}=\frac{5.5}{\sqrt{81}}= 0.611$

4 0

3 years ago