Answer:

Step-by-step explanation:
If RS is the diameter of the circle, then the midpoint of RS will be the center of the circle.



Equation of a circle: 
(where (h, k) is the center and r is the radius)
Substituting found center (-2, 2) into the equation of a circle:


To find
, simply substitute one of the points into the equation and solve:



Therefore, the equation of the circle is:

Answer:
D
Step-by-step explanation:
i took the test trust me
3% interest on 5,000 = 150
275 (the total amount wanted) - 150 (from initial investment)= 125
x (5%) =125
x (0.05)= 125
x/0.05)= 125/0.05
x=2500
you need to invest 2500 at 5% to get the additional 125
125 plus 150= 275
Answer:
Part A)
1) 
2)
Part B)
1) 
2)
Step-by-step explanation:
Part 1) x and y vary inversely and x=50 when y=5 find y when x=10 what is k?
we know that
A relationship between two variables, x, and y, represent an inverse variation if it can be expressed in the form
or 
step 1
<u>Find the value of k</u>
x=50 when y=5
substitute the values
------>
-----> 
The equation is equal to
or 
step 2
<u>Find y when x=10</u>
substitute the value of x in the equation and solve for y
Part B) x and y vary directly and x=6 when y=42 find k what is y when x=12
we know that
A relationship between two variables, x, and y, represent a direct variation if it can be expressed in the form
or 
step 1
<u>Find the value of k</u>
x=6 when y=42
substitute the values
------>
----->
The equation is equal to
or
step 2
<u>Find y when x=12</u>
substitute the value of x in the equation and solve for y
Answer:96%
Step-by-step explanation: 4 x 90 = 360, 87 + 88 + 89 = 264, 360 - 264 = 96