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3 years ago

What expression is equivalent to (3x^5+8x^3)-(7x^2-6x^3)

Mathematics

1 answer:

Musya8 [376]3 years ago

6 0

(3x^5 + 8x^3) - (7x^2 - 6x^3) = 3x^5 + 8x^3 - 7x^2 + 6x^3 = 3x^5 + 14x^3 - 7x^2

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What method would be best to use 53=4(x-3)^2-11

Veronika [31]

Answer:

x = 7 , -1

Step-by-step explanation:

SOLUTION :-

$4(x-3)^2-11 = 53$

Add 11 to both the sides.

$=> 4(x-3)^2-11+11=53+11$

$=> 4(x-3)^2 = 64$

Divide both the sides by 4.

$=> \frac{4(x-3)^2}{4} = \frac{64}{4}$

$=> (x-3)^2 = 16$

Root square both the sides.

$=> \sqrt{(x-3)^2} = \sqrt{16}$

$=> x-3 = +4 \; or -4$

Here , x will have two values -

1) $x-3 = 4$

$=> x = 4 + 3 = 7$

2) $x - 3 = -4$

$=> x = -4 + 3 = -1$

VERIFICATION :-

When x = 7 ,

$4(x-3)^2 - 11 = 4(7 - 3)^2 - 11$

$= 4 \times 4^2 - 11$

$= 4 \times 16 - 11$

$= 64 - 11$

$= 53$

When x = -1 ,

$4(x-3)^2 - 11 = 4(-1 - 3)^2 - 11$

$= 4 \times (-4)^2 - 11$

$= 4 \times 16 - 11$

$= 64 - 11$

$= 53$

7 0

3 years ago

I need help with this equation -11(-8×-15) my teacher said that I need to show my work pls help me.

Zielflug [23.3K]

First calculate (-8x-15)=120

Then multiply - 11x120

=-1320

3 0

3 years ago

The length of a rectangle is 5 m greater than the width. The perimeter is 150 m. find the width

Elza [17]

P = perimeter

Perimeter of a rectangle = l + l + w + w

or P = 2l + 2w

You know:

P = 150 m

l = w + 5 [length is 5 m greater than the width]

P = 2l + 2w Plug in what you know

150 = 2(w + 5) + 2w Simplify, distribute/multiply 2 into (w + 5)

150 = 2w + 10 + 2w

150 = 4w + 10 Subtract 10 to both sides of the equation

140 = 4w Divide 4 on both sides

35 = w

PROOF l = w + 5 ---> l = 40

P = 2l + 2w

150 = 2(40) + 2(35)

150 = 80 + 70

150 = 150

4 0

4 years ago

Find the Vertex given the Standard form y = -7x^2+x-112

Andreyy89

Answer:

The x= intercept is (0,0).

The y= inttercept is (0,0).

6 0

3 years ago

F(x)=2+3(2x+4)-8 is??

Vikki [24]

X = -6/5 I hope this helps

3 0

3 years ago