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Lady_Fox [76]
3 years ago
14

A company uses the formula T = 581s+150p to determine the total cost to purchase s computers and p printers. Which formula can b

e used to determine the number of printers purchased, given the total cost, t, and the number of computers purchased?​
Mathematics
1 answer:
Luba_88 [7]3 years ago
8 0

Answer: p= T/150 - 3.88s

Step-by-step explanation:

Hi, to answer this question we have to solve the equation for p.

T = 581s+150p

T -581s = 150p

(T -581s)/150 = p

T/150 - 3.88s =p

p= T/150 - 3.88s

For example if the total cost is $600 and the number of computers is 1:

p= 600/150-3.88 (1)

p=4-3.88

p= 0.12 per printer

Feel free to ask for more if needed or if you did not understand something.

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Can you give me an equation that equals to 31
lys-0071 [83]
There are m any examples of equations that equal 31. Here are a few:
17 + 14
30 + 1
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I like this one though (its 2 step)

(15 x 2) + 1

Hope this helped :)
7 0
3 years ago
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Please help me with the below question.
VMariaS [17]

By letting

y = \displaystyle \sum_{n=0}^\infty c_n x^{n+r}

we get derivatives

y' = \displaystyle \sum_{n=0}^\infty (n+r) c_n x^{n+r-1}

y'' = \displaystyle \sum_{n=0}^\infty (n+r) (n+r-1) c_n x^{n+r-2}

a) Substitute these into the differential equation. After a lot of simplification, the equation reduces to

5r(r-1) c_0 x^{r-1} + \displaystyle \sum_{n=1}^\infty \bigg( (n+r+1) c_n + (n + r + 1) (5n + 5r + 1) c_{n+1} \bigg) x^{n+r} = 0

Examine the lowest degree term \left(x^{r-1}\right), which gives rise to the indicial equation,

5r (r - 1) + r = 0 \implies 5r^2 - 4r = r (5r - 4) = 0

with roots at r = 0 and r = 4/5.

b) The recurrence for the coefficients c_k is

(k+r+1) c_k + (k + r + 1) (5k + 5r + 1) c_{k+1} = 0 \implies c_{k+1} = -\dfrac{c_k}{5k+5r+1}

so that with r = 4/5, the coefficients are governed by

c_{k+1} = -\dfrac{c_k}{5k+5} \implies \boxed{g(k) = -\dfrac1{5k+5}}

c) Starting with c_0=1, we find

c_1 = -\dfrac{c_0}5 = -\dfrac15

c_2 = -\dfrac{c_1}{10} = \dfrac1{50}

so that the first three terms of the solution are

\displaystyle \sum_{n=0}^2 c_n x^{n + 4/5} = \boxed{x^{4/5} - \dfrac15 x^{9/5} + \frac1{50} x^{13/5}}

4 0
2 years ago
I WILL MARK BRAINLIEST IF YOU CAN ANSWER THISSSS (9x10)/44+pi = xy what is xy and how did you find your answer?? After typing pl
melomori [17]

Answer:  1.9

Step-by-step explanation:

You want to multiply 9x10 which is 90.

Then you want to add 44+pi

now pi can be shown as 3.14 or 22 over 7

in this case you want to add 44 + 3.14 which gives you 47.14

now you want to divide 90/47.14 which gives you 1.90920661858 or in short

1.9

6 0
3 years ago
Two circles with different radii have chords AB and CD, such that AB is congruent to CD. Are the arcs intersected by these chord
emmainna [20.7K]

The arcs intersected by these chords are not congruent.

Given that two circles with different radii have chords AB and CD, such that AB is congruent to CD.

Let r₁ and r₂ be the radii of two different circles with centers O and O' respectively.

Assuming that the each of the ∠АОВ  and ∠CO'D is less than or equal to π.

Then, we have isosceles triangle AOB and CO'D such that,

AO = OB = r₁,

CO' = O'D = r₂,

Let us assume that r₁< r₂;

We can see that arc(AB) intersected by AB is greater than arc(CD), intersected by the chord CD;

arc(AB) > arc(CD)      .......(1)

Indeed,

arc(AB) = r₁ angle (AOB)

arc(CD) = r₂ angle (CO'D)

So, we have to prove that ;

∠AOB >∠CO'D       ......(2)

Since each angle is less than or equal to π, and so

∠AOB/2  and ∠CO'D/2 is less than or equal to π

it suffices to show that :

tan(AOB/2) >tan(CO'D/2) ......(3)

From triangle AOB :

tan(AOB/2) = AB/(2*r₁)

tan(CO'D/2) = CD/(2*r₂)

Since AB = CD and r₁ < r₂ (As obtained from the result of (3) ), therefore, arc(AB) > arc(CD).

Hence, for two circles with different radii have chords AB and CD, such that AB is congruent to CD but the arcs intersected by these chords are not congruent.

Learn more about congruent from here brainly.com/question/1675117

#SPJ1

6 0
2 years ago
If i have the angle and hypotenuse how to find the other sides
artcher [175]
You should find the attached graphic to be helpful for what you need to know.

7 0
3 years ago
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