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2 years ago

Convert 6.2x10^5 mm to km. (please show the steps to how you did the problem.)

Mathematics

2 answers:

erma4kov [3.2K]2 years ago

4 0

Answer:

0.62km

Step-by-step explanation:

1 mm= .000001km

620,000mm= 0.62km

Multiply 620,000 by 0.000001

Elenna [48]2 years ago

4 0

Answer:

$0.62$ km

Step-by-step explanation:

$6.2 \times {10}^{5} \\ 6.2 \times 100000 \\ = 0.62$ km I hope this helps you

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3 years ago

Find a formula for the described function. A rectangle has perimeter 16 m. Express the area A of the rectangle as a function of

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Part A:

Let the length of one of the sides of the rectangle be L, then the length of the other side is obtained as follow.

Let the length of the other side be x, then

$2(L+x)=16 \\ \\ \Rightarrow L+x=8 \\ \\ \Rightarrow x=8-L$

Thus, if the length of one of the side is x, the length of the other side is 8 - L.

Hence, the area of the rectangle in terms of L is given by

$L(8 - L) = 8L-L^2$

Part B:

To find the domain of A

Recall that the domain of a function is the set of values which can be assumed by the independent variable. In this case, the domain is the set of values that L can take.

Notice that the length of a side of a rectangle cannot be negative or 0, thus L cannot be 8 as 8 - 8 = 0 or any number greater than 8.

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Therefore,

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3 years ago

Simplify (5r^2t)^2(3r^0t^4)

Snezhnost [94]

Answer

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3 years ago

On a standardized test with a normal distribution the mean score was 67.2. The standard deviation was 4.6. What percent of the d

Reika [66]

Answer:

P ( -1 < Z < 1 ) = 68%

Step-by-step explanation:

Given:-

- The given parameters for standardized test scores that follows normal distribution have mean (u) and standard deviation (s.d) :

u = 67.2

s.d = 4.6

- The random variable (X) that denotes standardized test scores following normal distribution:

X~ N ( 67.2 , 4.6^2 )

Find:-

What percent of the data fell between 62.6 and 71.8?

Solution:-

- We will first compute the Z-value for the given points 62.6 and 71.8:

P ( 62.6 < X < 71.8 )

P ( (62.6 - 67.2) / 4.6 < Z < (71.8 - 67.2) / 4.6 )

P ( -1 < Z < 1 )

- Using the The Empirical Rule or 68-95-99.7%. We need to find the percent of data that lies within 1 standard about mean value:

P ( -1 < Z < 1 ) = 68%

P ( -2 < Z < 2 ) = 95%

P ( -3 < Z < 3 ) = 99.7%

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3 years ago

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Answers and work is written in the picture. Hope this helps!!

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