Answer:
I think the answer is 20 teacher tickets and 460 student tickets.
Given a square ABCD and an equilateral triangle
DPC and given a chart with which
Jim is using to prove that triangle APD is
congruent to triangle BPC.
From the chart, it can be seen that Jim proved that two corresponding sides of both triangles are congruent and that the angle between those two sides for both triangles are also congruent.
Therefore, the justification to complete Jim's proof is "SAS postulate".
<h3>
Answer: A) 6</h3>
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Explanation:
Plug n = 6 and r = 5 into the nCr combination formula

Or you could use the shortcut

Yet another path you could take is to use Pascal's Triangle. Locate the row that starts with 1,6,... and then locate the second to last item. That value in the triangle is 6.
A real world interpretation is to consider having 6 people and you are selecting 5 of them to form a group where order doesn't matter. How many ways are there to do this? Well there are 6 such ways because there are 6 ways to leave someone out of the group.
The angle could be named these two different ways:
angle CAD or angle DAC.