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krok68 [10]
3 years ago
14

In parallelogram ABCD, what is BDC?

Mathematics
2 answers:
yKpoI14uk [10]3 years ago
7 0

Answer:

∠ BDC = 25°

Step-by-step explanation:

Since ABCD is a parallelogram , then

AB and DC are parallel , so

∠ BDC = ∠ ABD = 25° ( alternate angles )

zavuch27 [327]3 years ago
5 0

Answer:

25

Step-by-step explanation:

<ABD=<BDC

Check it out

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Find the sum.<br> 48 + 45 + 42+...+(-81) + (-84)
Agata [3.3K]

Answer:

look below

Step-by-step explanation:

i dont know what that +... thing is

but when youre adding the negatives youre really just adding that number so this is just

48+45+42+81+84

45+42 is 87

now we have

48 + 87 + 81 + 84

87 + 81 is 168

48 + 84 is 132

now we have

168 + 132 and that is exactly 300

again dont know what the ... is so cant help you there

4 0
2 years ago
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The first answer is figure B
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4 0
3 years ago
Need help with this geometric question ASAP, Thank you
USPshnik [31]
Because LP squared plus PM squared must equal LM therefore LP cannot be less.
3 0
3 years ago
V=1wh how do i solve for w
postnew [5]

Answer:

W=v/h.

Step-by-step explanation:

V=1wh

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6 0
2 years ago
Help me solve this please
damaskus [11]

1) A quadratic will have no real roots when its discriminant is negative


0 = ax^2 + bx + c = x^2 + 2k x + (4k-3)


d = b^2 - 4ac =  (2k)^2 - 4(1)(4k-3) = 4k^2 - 16k + 12 < 0


Dividing by 4,


k^2 - 4 k + 3 < 0 \quad\checkmark


We have a positive coefficient on k^2 so this parabola is a CUP (concave up positive) so has a minimum at the vertex. If the vertex y value is less than zero, the inequality will be true in the range between the zeros.


(k-3)(k-1)


That's true for


1 < k < 3


2) We look for the meet of the line and the parabola:


2x + k + 2 = 2x^2 + (k+2)x + 8


0 = 2x^2 + kx + (6-k)


For two intersections we need a positive discriminant:


k^2 - 4(6-k)(2) > 0


k^2 + 8k - 48 > 0


(k+12)(k-4) > 0


That's means two negative or two positive, so


k < 12 or k > 4


6 0
3 years ago
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