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PolarNik [594]
3 years ago
10

Need help!!!

id="TexFormula1" title=" \frac{3 - 3 \sqrt{3a} }{4 \sqrt{8a} } " alt=" \frac{3 - 3 \sqrt{3a} }{4 \sqrt{8a} } " align="absmiddle" class="latex-formula">
Mathematics
2 answers:
madreJ [45]3 years ago
8 0
      3 - 3√3a
= -----------------
       4√8a

      3 - 3√3a
= -----------------
       8√2a

      (3 - 3√3a) √2a 
= ----------------------
       8 √2a √2a 

      3√2a  - 3a√6
= ----------------------
          16a

      3(√2a  - a√6)
= ----------------------
          16a

hope it helps
Klio2033 [76]3 years ago
5 0
So, to simplify, find what can be changed and what can't.
You can get rid of <em>a</em>, because whether they are both inside or out of a square root function (can't be mixed), they can be gotten rid of.
So, you will end up with \frac{3-3 \sqrt{3} }{4 \sqrt{8} }.
But, that's not the simplest form.
The square root on the bottom still can be simplified.
So, find a factor in 8 that can have a perfect square. 2,4
2,2,2
Since 4 is a perfect squared (you find a pair of multiples when factored again), the simple version is 2\sqrt{2}, but you have to multiply the number on the outside by the number already there.
4×2=8
So, your simplest equation would be \frac{3-3 \sqrt{3} }{8 \sqrt{2} }.
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The function which is same as the function y = 3cos(2(x +π/2)) -2 is: Option A: y= 3sin(2(x + π/4)) - 2

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(this all positive negative refers to the fact that if you use given angle as input to these functions, then what sign will these functions will evaluate based on in which quadrant does the given angle lies.)

Here, the given function is:

y= 3\cos(2(x + \pi/2)) - 2

The options are:

  1. y= 3\sin(2(x + \pi/4)) - 2
  2. y= -3\sin(2(x + \pi/4)) - 2
  3. y= 3\cos(2(x + \pi/4)) - 2
  4. y= -3\cos(2(x + \pi/2)) - 2

Checking all the options one by one:

  • Option 1: y= 3\sin(2(x + \pi/4)) - 2

y= 3\sin(2(x + \pi/4)) - 2\\y= 3\sin (2x + \pi/2) -2\\y = -3\cos(2x) -2\\y = 3\cos(2x + \pi) -2\\y = 3\cos(2(x+ \pi/2)) -2

(the last second step was the use of the fact that cos flips its sign after pi radian increment in its input)
Thus, this option is same as the given function.

  • Option 2: y= -3\sin(2(x + \pi/4)) - 2

This option if would be true, then from option 1 and this option, we'd get:
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Thus, this option is not same as the given function.

  • Option 3: y= 3\cos(2(x + \pi/4)) - 2

The given function is y= 3\cos(2(x + \pi/2)) - 2 = 3\cos(2x + \pi) -2 = -3\cos(2x) -2

This option's function simplifies as:

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  • Option 4: y= -3\cos(2(x + \pi/2)) - 2

The given function simplifies to:y= 3\cos(2(x + \pi/2)) - 2 = 3\cos(2x + \pi) -2 = -3\cos(2x) -2

The given option simplifies to:

y= -3\cos(2(x + \pi/2)) - 2 = -3\cos(2x + \pi ) -2\\y = 3\cos(2x) -2

Thus, this function is not same as the given function.

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