Answer:
toString is right Answer
Explanation:
If you want to represent any object as a string, toString() method comes into existence.
The toString() method returns the string representation of the object.
If you print any object, java compiler internally invokes the toString() method on the object. So overriding the toString() method, returns the desired output, it can be the state of an object etc. depends on your implementation.
The technology is being used when you are sent an email saying you can track your package is known to be a scan code.
<h3>What are code-scanning technology?</h3>
This is known to be called a barcode reader or simply say a barcode scanner.
It is seen as a kind of an optical scanner that tends to read printed barcodes, as well as be able to decode the data that are found in the barcode and transmit the data to a computer.
Hence, The technology is being used when you are sent an email saying you can track your package is known to be a scan code.
Learn more about scan code from
brainly.com/question/24937533
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A destination port number at the transport layer identifies which software application on a computer should receive the data transmission: True.
<h3>What is the
transport layer?</h3>
The transport layer can be defined as one of the seven layers of the open systems interconnection (OSI) model and it is responsible for routing messages through an active computer network while selecting the best transmission path from the source to the destination device.
In Computer networking, a destination port number at the transport layer is saddled with the responsibility of identifying which software application on a computer should receive the data transmission.
Read more on transport layer here: brainly.com/question/26177113
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The time that it takes the computer to receive acknowledgment for a packet is 0.1667 seconds. The time it takes to send out a packet is 4 x 10⁻³seconds
<h3>1 The acknowledgment time for the packet</h3>
speed = 2.4x108m/s
Distance = 40000 km,
Time = distance/ speed
= 40000 x10³/ 2.4x10⁸m/s
= 0.1667
The time that it take is 0.1667 seconds.
b. Number of bytes = 5000
5000x 8 = 40000bits
10 mbps = 10000 kbps
10000 kbps = 10000000
packet size / bit rate = 40000/10000000
= 4 x 10⁻³seconds to send a packet out
Read more on computer bandwith here: brainly.com/question/27020560
